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Given that Jaquelyn was tardy on Monday, there is a 12 percent chance she will be late on Tuesday as well.
What is the Probability?
How likely it is that a stated event would occur is assessed using probability. The event would have a probability of 1 if it happened with certainty. The probability of an occurrence would be zero if it were absolutely guaranteed that it would not occur.
As getting late on Monday and Tuesday are independent events, their probabilities can be multiplied.
So the probability of getting late on Tuesday, given she was late to school on Monday = Probability of being late on Monday x Probability of she being late on Monday and she is late on Tuesday 60% of the time.
= 0.2 x 0.6
= 0.12
Thus the approximate probability that Jaquelyn will be late on Tuesday, given she was late to school on Monday will be 0.12
Learn more about Probability here :
brainly.com/question/11234923
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First, we are going to determine the number of drops that needs to be administered by dividing the total volume by the volume per drop. Since, 1 cc (cm³) is equal to 1 mL then, 1000 cc is equal to 1000 mL.
n = (1000 mL)(15 drop/1 mL) = 15000 drops
Then, divide the number of drops by the number of drops per minute.
N = (15000 drops)/ (50 drop/min) = 300 mins
Answer: 300 mins or 5 hours
Answer:
(x)^2 (y)^2
---------- + --------- = 1
4 3
Step-by-step explanation:
The standard equation for an ellipse is
(x-h)^2 (y-k)^2
---------- + --------- = 1
a^2 b^2
The center is at (h,k)
The vertices are at (h±a, k)
The foci are at (h±c,k )
Where c is sqrt(a^2 - b^2)
It is centered at the origin so h,k are zero
(x)^2 (y)^2
---------- + --------- = 1
a^2 b^2
The center is at (0,0)
The vertices are at (0±a, 0)
The foci are at (0±c,0 )
The vertices are (±2,0) so a =2
The foci is 1
c = sqrt(a^2 - b^2)
1 = sqrt(2^2 - b^2)
Square each side
1 = 4-b^2
Subtract 4 from each side
1-4 = -b^2
-3 = -b^2
3= b^2
Take the square root
b=sqrt(3)
(x)^2 (y)^2
---------- + --------- = 1
4 3
