Question

What is the percent by mass of water in copper (II) sulfate pentahydrate (CuSO4 · 5H4O)? Type in your answer using one decimal place.

Answer 1

Percentage by mass of water in CuSO4.5H20 is 36.07% .

In this problem we have - copper(II) sulfate pentahydrate and it's molecular formula is (CuSO₄.5H₂O) .

There are 5 molecules of water are present.

Now we calculate it's molar mass-

We know that-

molar mass of Cu = 63.5u

Molar mass of SO₄ = 96 u

Molar mass of H₂O = 18 u

Now, molar mass of (CuSO₄.5H₂O) = 63.5 + 96 + 5 × 18

Now, molar mass of (CuSO₄.5H₂O) = 249.5u

And mass of water in CuSO₄.5H₂O = 90 u

now mass percentage of water = mass of water ÷ Total mass ×100

now mass percentage of water = 90 ÷ 249.5 × 100

now mass percentage of water =  36.07 %

So we find out mass percent by dividing given mass with total mass and then multiplying it with hundred and it came out to be 36.07 % .

Learn more about mass percent here: brainly.com/question/13896694

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