First I find the individual widget weight
81 - 73 = 2x
8 = 2x
x = 4
Then I find how many widgets were left
73 - 1 = 4y
72 = 4y
18 = y
Y is the amount of widgets left, therefore the amount left is 18
Answer:
5(d - 2) = 45
Step-by-step explanation:
Solve the given equation for d
3(d + 1) = 4(d - 2) ← distribute parenthesis on both sides
3d + 3 = 4d - 8 ( subtract 3d from both sides )
3 = d - 8 ( add 8 to both sides )
11 = d
Then
5(d - 2) = 5(11 - 2) = 5(9) = 45
Step-by-step explanation:
Below is an attachment containing the solution.
length of pipe= 30m
Inside dia. = 1.2m
Outside dia. = 1.8m
Volume of concrete= (outside dia. - inside dia.)h
V= (pi)
v= [(3.14*0.9*0.9)-(3.14*0.6*0.6)]30
v= (3.3534-1.1304)30
v=(2.233)30 = 66.690m cube
since it's volume the answer 66.690 is in cubic meters.
Answer:
x = -8
y = 7
Step-by-step explanation:
5x + 7y = 9
2x - 3y = -37
1.) First, multiply each side to match either y-values or x-values. (In this example, we'll use match x-values)
10x + 14y = 18 (multiplied by 2)
10x - 15y = -185 (multiplied by 5)
2.) Then, subtract the entirety of one equation to isolate the y-value.
10x + 14y = 18
-10x + 15y = 185
3.) Add and subtract values and divide to find y.
29y = 203
y = 7
4.) Plug-in y to solve for x into one equation, or repeat steps 1-3.
15x + 21y = 27
14x - 21y = -259
29x = -232
x = -8
