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2 years ago

Is this relationship linear, exponential, or neither. x -12 -6 0 6 y 9 12 20 40

Mathematics

1 answer:

Diano4ka-milaya [45]2 years ago

5 0

Answer:

This appears to be exponential based on the plot of these points

Step-by-step explanation:

See image

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Solve for a PLS HURRY

ladessa [460]

Answer:

I guess it is d

Step-by-step explanation:

make it braintliest please

3 0

3 years ago

Read 2 more answers

First to answer correctly gets brainliest

Readme [11.4K]

Answer:

240 $\leq$ 12.5p + 65

14 $\leq\\$ p

Step-by-step explanation:

I'll explain the equation in different parts

12.5p - Since the number of times he visits is unknown, it has to be a variable. With each visit, however, he earns 12.5 points.

65 - This is a set value that remains constant

240 $\leq\\$ - Since he needs AT LEAST 240 points, he needs 240 points or more to get his free ticket

As for solving the equation just use properties of equality

240 $\leq$ 12.5p + 65

175 $\leq$ 12.5p

14 $\leq\\$ p

7 0

3 years ago

Snapdragon plants have a gene that determines the presence of chlorophyll. The dominant allele (C) causes the plant to make chlo

AleksAgata [21]

Answer: i)For X = (0,1) then P(x) = (1/3, 2/3)

ii) Then p=(2/3) as n=8

iii) 0.06828

Step-by-step explanation:

Use binomial distribution:

Probability of being yellow (by having 1 recessive allele) is 2/3. This is a binomial distribution with p=2/3. And since there are 8 selections, our n is 8. So p=(2/3), n=8.

Recall that in binomial distribution P(X=x) = C(n,x) × p^x × (1-p)^n-x.

So for 3 out of 8, it means x=3 and n=8.

Our equation becomes P(exactly three Snapdragon are yellow) = P(X=3) = (8C3) × (2/3)³ × (1/3)5 = 0.06828

7 0

3 years ago

Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand

Misha Larkins [42]

Answer:

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

Solution:

Given, Scores on a test are normally distributed with a mean of 81.2

And a standard deviation of 3.6.

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

$\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2$

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0

3 years ago

What are the answers to these four questions

Diano4ka-milaya [45]

Number 5 is 3.8
number 6 is yes, she will bc if you multiply 14,2 by 8, it will be less than 88.3
number 7 is about .11
number 8 is about 4.285

8 0

3 years ago