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natima [27]
2 years ago
8

What is the solution to the equation?  5(8 + 7) = 5 • x + 5 • 7   A. x = 1   B. x = 5   C. x = 7   D. x = 8

Mathematics
1 answer:
Aleks [24]2 years ago
7 0
5(8+7)=5\cdot x+5\cdot7\\\\x=8\\\\Answer:D\\\\5\cdot x+5\cdot7=\underline{5}\cdot x+\underline{5}\cdot7=\underline{5}\cdot(x+7)=5\cdot(8+7)\iff x=8
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Each triangle in the net below has a base of 6 centimeters and a height of 8 centimeters. What is the surface area, in square ce
Misha Larkins [42]

The area of a triangle is 1/2 x base x height.

The area of the triangle is 1/2 x 6 x 8 = 24 square cm.

There are 4 identical triangles so 24 x 4 = 96 square cm.

The area of the square base = 6 x 6 = 36 square cm.

Total area = 96 + 36 = 132 square cm.

5 0
2 years ago
Write an integer for: a deposit of $45 * Plz help fast!
Mice21 [21]

Answer:

$45

Step-by-step explanation:

  1. A deposit is positive, so the integer will be positive.
  2. An integer is a whole number that's not a fraction, so a positive integer for 45, would be 45.

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6 0
3 years ago
Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for the function. (
Mrrafil [7]

Answer:

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

Step-by-step explanation:

From exercise we have the next function y = 6 sec(3x).

We know that Maclaurin series for the function sec x, have the following form:

\sec x=1+\frac{x^2}{2}+\frac{5x^4}{24}+...

So, for the given function y = 6 sec(3x), we get:

y = 6 \sec(3x)=6+27x^2+\frac{405x^4}{4}+...

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

6 0
2 years ago
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gogolik [260]

Answer:

If you simplify it you get d^2-4d

Step-by-step explanation:

6 0
2 years ago
Which answer choice is correct?
lana66690 [7]
I’m pretty sure it is A
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