If you want the area of the entire trapeziod.
The formula for area of a trapeziod is:
1/2h(b₁+b₂)
So the equation applied to the trapeziod is:
2.5(20+12)
20+12 is 32. 32 multiplied by 2.5 is 80.
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Ｙｏｕｒ ａｎｓｗｅｒ ｉｓ ８０.</em></u></h3>
Solution:
<u>A few tips...</u>
- Tip-1: If "+" and "-" are multiplied, it gives a result of "-".
- Tip-2: If "-" and "-" are multiplied, it gives a result of "+".
- Tip-3: If "+" and "+" are multiplied, it gives a result of "-".
<u>Changing the sign of the given equation.</u>
- 1.25 + (-0.75)
- => 1.25 - 0.75 [Sign changes according to tip-1.]
This could only mean that the arrow would go to <u>1.25 units forward.</u> Then a second arrow will be drawn to go <u>0.75 units back.</u>
The graph that matches with the above info is Option C.
Answer:
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
Step-by-step explanation:
Given
Volume of a box = length × breadth × height= l×b×h
In this case the box have a square base. i.e l=b
Volume V = l^2 × h
The surface area of a square box
S = 2(lb+lh+bh)
S = 2(l^2 + lh + lh) since l=b
S = 2(l^2 + 2lh)
Given that the box is open top.
S = l^2 + 4lh
And Surface Area of the box is 1200cm^2
1200 = l^2 + 4lh ....1
Making h the subject of formula
h = (1200 - l^2)/4l .....2
Volume is given as
V = l^2 × h
V = l^2 ×(1200 - l^2)/4l
V = (1200l - l^3)/4
the maximum point is at dV/dl = 0
dV/dl = (1200 - 3l^2)/4
dV/dl = (1200 - 3l^2)/4 = 0
3l^2= 1200
l^2 = 1200/3 = 400
l = √400
I = 20cm
Since,
h = (1200 - l^2)/4l
h = (1200 - 20^2)/4×20
h = (800)/80
h = 10cm
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
Answer:
Can you describe this question
Step-by-step explanation:
Answer:
amebo soup
Step-by-step explanation:
i love it
