19. The formula for finding the volume of a sphere is 4/3πr^3
The problem says the radius is 9.25 cm.
Just plug in the numbers and solve:
4/3(3.14)(9.25^3)
9.25^3 = ~791.45
4/3(3.14)(791.45)
4/3 • 3.14 = ~4.19
4.19 • 791.45 = 3316.1755
It says to round to 2 decimal places so the answer to this question would be 3316.18.
That means 3316.18 is the volume of the sphere.
20. It's always best to change words into an equation.
-16 - w
w = -23
Plug in the number to the variable:
-16 - (-23)
Double negatives (a negative being subtracted) turn into a plus (positive being added).
-16 + 23 = 7
So the answer is 7.
25. Complementary angles are angles with a sum of 90º.
If angle A is 27º, just subtract that from 90º to get the measure of angle B.
90 - 27 = 63
So angle B is 63º, and the answer is A.
Finding the upper and lower bounds for a definite integral without an equation is pretty hard because how can we find the upper and lower bounds of definite integral if there is no equation given. But I will teach you how to find the lower and upper bounds of a definite integral, when the equation is like this
So, i integrate this,

I know I have a minimum at x=3 because;
f(t )= t^2 − 6t + 11
f′(t) = 2
t−6 = 0
2(t−3) = 0
t = 3
f(5) = 4
f(1) = −4
.0091 rounded to the nearest hundredths is .01.
If you Multiply the equation you will get 9x+11
Answer:
The most appropriate inference procedure for the investigation is;
a. A linear regression t-interval for the slope
Step-by-step explanation:
Given that the slope of an horizontal line is zero, we have that there is no change in the y (dependent) variable when there is a change in the x-variable, therefore, it is important to find the true relationship between the two variables, 'x', and 'y'
The confidence interval of the slope is calculated and analyzed to determine if it excludes or includes, 0, such that, if the confidence interval exclude 0, then, it is unlikely that the slope is 0, therefore, there the relationship between the variables, 'x', and 'y' is significant
Therefore, a linear regression t-interval for the slope is most appropriate.