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1 year ago

Ayuda porfaaa JHAKJAH es para hoy y no entiendo un klo

Mathematics

1 answer:

Bond [772]1 year ago

3 0

A. +27
B. +4
C.+21

A. -16
B. 23
C. 3
D. -70
E. -20

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The average weight of the top 5 fish at a fishing tournament was 13.6 pounds. Some of the weights of the

lapo4ka [179]

Answer: Carla P. 15.1

Step-by-step explanation:

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3 years ago

What is the volume of the following triangular prism?

BlackZzzverrR [31]

Answer: 3000cm3

To find the area you need to find the area of the triangle and multiply that by the height of the prism.

The area of the triangle is

.5*12*10 = 60

And the height is .5m = 50cm

So the area will be

60*50 = 3000

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3 years ago

Read 2 more answers

3. Find a in the given figure.

Anvisha [2.4K]

Answer:

Step-by-step explanation:

Angles a and b are opposite, so they are equal. The same is true for angles O and 3b.

So, the four angles are actually (starting from the left and going clockwise) 3b,b,3b,b

These four angles sum up to 360, so we have

$3b+b+3b+b =8b = 360 \iff b = \dfrac{360}{8} = 45$

And since a and b were the same, a is also 45 degrees.

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3 years ago

Is this linear or exponential? or neither

Brrunno [24]

Answer:

Exponential

Step-by-step explanation:

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2 years ago

Find the standard deviation of 21, 31, 26, 24, 28, 26

Vesnalui [34]

Given the dataset

$x = \{21,\ 31,\ 26,\ 24,\ 28,\ 26\}$

We start by computing the average:

$\overline{x} = \dfrac{21+31+26+24+28+26}{6}=\dfrac{156}{6}=26$

We compute the difference bewteen each element and the average:

$x-\overline{x} = \{-6,\ 5,\ 0,\ -2,\ 2,\ 0\}$

We square those differences:

$(x-\overline{x})^2 = \{36,\ 25,\ 0,\ 4,\ 4,\ 0\}$

And take the average of those squared differences: we sum them

$\displaystyle \sum_{i=1}^n (x-\overline{x})^2=36+25+4+4+0+0=69$

And we divide by the number of elements:

$\displaystyle \sigma^2=\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n} = \dfrac{69}{6} = 11.5$

Finally, we take the square root of this quantity and we have the standard deviation:

$\displaystyle\sigma = \sqrt{\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n}} = \sqrt{11.5}\approx 3.39$

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3 years ago