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Stels [109]
2 years ago
11

Ayuda porfaaa JHAKJAH es para hoy y no entiendo un klo

Mathematics
1 answer:
Bond [772]2 years ago
3 0
A. +27
B. +4
C.+21

A. -16
B. 23
C. 3
D. -70
E. -20
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Why is b ≠ 1 a condition for f(x) = abx (x is a exponent i cant put it for some reason)?
timurjin [86]

Answer:

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Bingel [31]
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Read 2 more answers
What 2 numbers multiply to be -14 and add to be -3
Svetach [21]
Xy = -14
x + y = -3

xy = -14
\frac{xy}{x} = \frac{-14}{x}
y = \frac{-14}{x}

x + y = -3
x + \frac{-14}{x} = -3
\frac{x^{2}}{x} + \frac{-14}{x} = -3
\frac{x^{2} - 14}{x} = -3
x^{2} - 14 = -3x
x^{2} + 3x - 14 = 0
x = \frac{-(3) \± \sqrt{(3)^{2} - 4(1)(-14)}}{2(1)}
x = \frac{-3 \± \sqrt{9 + 56}}{2}
x = \frac{-3 \± \sqrt{65}}{2}
x = \frac{-3 \± 8.06}{2}
x = -1.5 \± 4.03
x = -1.5 + 4.03    or    x = -1.5 - 4.03
x = 2.53    or    x = -5.53

        x + y = -3
   2.53 + y = -3
 - 2.53         - 2.53
              y = -5.53
        (x, y) = (2.53, -5.53)
         
         x + y = -3
  -5.53 + y = -3
+ 5.53         + 5.53
              y = 2.53
        (x, y) = (-5.53, 2.53)

The two numbers that multiply to -14 and add up to -3 are -5.53 and 2.53.
8 0
3 years ago
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