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2 years ago

? Question

Mathematics

1 answer:

lord [1]2 years ago

5 0

See below for the explanation on how to determine the coordinates.

<h3>How to determine the coordinates?</h3>

The question is incomplete, and the missing parameters cannot be found.

So, I will give a general explanation on how to determine coordinates.

Assume that the start point of the buoy is

(x, y)

And the length of the buoy is k.

Depending on the position of the bouy on the coordinate plane, the endpoint can be any of the following coordinates (x - h, y), (x + h, y), (x, y + h) and (x, y - h)

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Susan's grandparents have a clock in their home that chimes on every hour each day. How many times will the clock chime in a yea

Leto [7]

Just look up how many hours are there In a year

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3 years ago

The number of loaves of bread purchased and the total cost of the bread in dollars can be modeled by the equation c = 3. 5b. Whi

Allisa [31]

You can use the fact that number of breads purchased cannot be negative since a customer either buys them or not and usually do not sell to the shopkeeper.(if somehow they end up selling to shop owner, then yes that will go in negative, but we'll assume it is wrong in most cases as generally shop owners are there to sell stuffs).

The third table of values matches the equation and includes only viable solutions.

<h3>What is a viable solution here?</h3>

It is talking about those solutions which are seen in real world. As stated above, a customer either buys the bread or not, thus number of breads sold will be either positive or 0(in case of no selling). Thus, we cannot have number of breads as negative.

Such solutions which are correct in the real world context here are called here as viable solutions.

<h3>Checking one by one all the tables for them being matched with table and viability</h3>

For first table, the number of breads are in negative, thus it is not going to have viable solution.

For second table, we have:

b = 0 thus c = 3.5b = 3.5 times 0 = 0 which is correctly given in second column.

b = 0.5, thus c = 3.5b = 3.5 times 0.5 =1.75 which is correctly given.

b = 1, thus c= 3.5 times 1 = 3.5 which is correctly given

b = 2001.5 thus c = 3.5 times 2001.5 = 7005.25 which is not correctly given, thus wrong.

For third table, we have:

b = 0, thus $c = 3.5 \times 0 = 0$ , correctly given in second column.

b = 3, thus $c = 3.5 \times 3 = 10.5$ , correctly given.

b = 6, thus $c = 3.5 \times 6 = 21$ , correctly given.

b = 9, thus $c = 3.5 \times 9 = 31.5$ , correctly given.

Thus, the third table of values matches the equation and includes only viable solutions.

Learn more about purchasing to cost relation here:
brainly.com/question/13727919

8 0

3 years ago

I need help with plz

makkiz [27]

32. p is 3r-1. (3r-1)+r=43. 4r-1=43. 4r=44. r=11. p=3r-1. p=3(11)-1. p=32.

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4 years ago

The employees of a firm that manufactures insulation are being tested for indications of asbestos in their lungs. The firm is re

diamong [38]

Answer:

0.070

Step-by-step explanation:

Y = number on trial

Y has a negative binomial distribution

r = 3

P = 30% = 0.3 probability of positive indication.

P(Y = 11) probability of 11 employees that must be tested to get 3 positives

Y-1Cr-1*p^r*q^(y-r)

Y-1 = 11-1 = 10

r-1 = 3 -1 = 2

10C2 x 0.3³x0.7⁸

45x0.027x0.05764801

= 0.070

This is the probability that 11 employees must be tested to get 3 positives.

8 0

3 years ago

If [infinity] cn8n n = 0 is convergent, can we conclude that each of the following series is convergent? (a) [infinity] cn(−3)n

pashok25 [27]

Answer:

a) we know that this is convergent.

b) we know that this might not converge.

Step-by-step explanation:

Given the $\sum^\infty_{n=0}C_n8^n$ is convergent

Therefore,

(a) $\sum^\infty_{n=0}C_n(-3)^n$ The power series $\sum C_nx^n$ has radius of convergence at least as big as 8. So we definitely know it converges for all x satisfying -8<x≤8. In particular for x = -3

∴ $\sum^\infty_{n=0}C_n(-3)^n$ is convergent.

(b) $\sum^\infty_{n=0}C_n(-8)^n$ -8 could be right on the edge of the interval of convergence, and so might not converge

8 0

3 years ago