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2 years ago

? Question

Mathematics

1 answer:

lord [1]2 years ago

5 0

See below for the explanation on how to determine the coordinates.

<h3>How to determine the coordinates?</h3>

The question is incomplete, and the missing parameters cannot be found.

So, I will give a general explanation on how to determine coordinates.

Assume that the start point of the buoy is

(x, y)

And the length of the buoy is k.

Depending on the position of the bouy on the coordinate plane, the endpoint can be any of the following coordinates (x - h, y), (x + h, y), (x, y + h) and (x, y - h)

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Determine whether or not the given value is a solution for the equation. Answer Yes or No

igor_vitrenko [27]

Y=24 is a solution for the equation.

y/12=2 is solved by multiplying both sides by 12 to get y by itself. so you'd end up multiplying 2 • 12 which equals 24.

5 0

2 years ago

A pencil and a ruler cost 2.50 together. The ruler costs $1.00 more than the pencil. How much is the pencil

Alenkasestr [34]

P + r = 2.50
r = p + 1

p + p + 1 = 2.50
2p + 1 = 2.50
2p = 2.50 - 1
2p = 1.50
p = 1.50/2
p = 0.75 <=== pencil cost 75 cents

r = p + 1
r = 0.75 + 1
r = 1.75 .....ruler cost 1.75

6 0

3 years ago

Read 2 more answers

BRAINLIEST AND 100 POINTS. Please help by explaining how you got the answer

spayn [35]

Answer:

it may be A log x ........

4 0

3 years ago

Determine

Luden [163]

Answer:

$\mu_{x} = 64, \sigma_{x} = 12.83$

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu_{x} = \mu$ and standard deviation $\sigma_{x} = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 64, \sigma = 77, n = 36$

$\mu_{x} = 64, \sigma_{x} = \frac{77}{\sqrt{36}} = 12.83$

7 0

3 years ago

HELPPPP ME PLZZZZ!!!!!!

mihalych1998 [28]

<h3>Answers:</h3>

14. Each leg is $21\sqrt{2}$ units long.

15 (a). The longer leg is $7\sqrt{3}$ units long

15 (b). The hypotenuse is $14$ units long

=====================================================

Explanations:

For a 45 degree right triangle, aka 45-45-90 triangle, the hypotenuse is equal to sqrt(2) times the short leg. Algebraically we can say

$y = x\sqrt{2}$ where x is the leg and y is the hypotenuse

Let's solve for x

$y = x\sqrt{2}\\\\x\sqrt{2} = y\\\\x = \frac{y}{\sqrt{2}}\\\\x = \frac{y\sqrt{2}}{\sqrt{2}*\sqrt{2}} \ \text{rationalizing denominator}\\\\x = \frac{y\sqrt{2}}{2}\\\\$

Now plug in the given hypotenuse y = 42, this leads to,

$x = \frac{y\sqrt{2}}{2}\\\\x = \frac{42\sqrt{2}}{2}\\\\x = \frac{42}{2}\sqrt{2}\\\\x = 21\sqrt{2}\\\\$

---------------------------

For a 30-60-90 triangle, the hypotenuse is double that of the short leg. So the hypotenuse is 2*7 = 14.

The longer leg is equal to sqrt(3) times the short leg. The longer leg is $7\sqrt{3}$

5 0

3 years ago