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Korvikt [17]
2 years ago
12

Find the equation of the horizontal line at a height of -3.9.

Mathematics
1 answer:
Sholpan [36]2 years ago
3 0

The equation of the line will be y = -3.9, and the height after rounding off will be -4.

<h3>What is a straight line?</h3>

A straight line is a combination of endless points joined on both sides of the point.

The slope 'm' of any straight line is given by:

\rm m =\dfrac{y_2-y_1}{x_2-x_1}

The horizontal line can be defined as:

y = a

Where a is the constant.

Here a = -3.9

y = -3.9

The height = -3.9 ≈ -4

Thus, the equation of the line will be y = -3.9, and the height after rounding off will be -4.

Learn more about the straight line here:

brainly.com/question/3493733

#SPJ1

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7 0
4 years ago
Read 2 more answers
A company makes 140 bags. 39 of the bags have buttons but no zips. 21 of the bags have zips but no buttons. 23 of the bags have
sleet_krkn [62]

Subtraction is a mathematical operation that reflects the removal of things from a collection. The number of bags that zips on them is 78.

<h3>What is subtraction?</h3>

Subtraction is a mathematical operation that reflects the removal of things from a collection. The negative symbol represents subtraction.

Given the number of bags that the company makes is 140. 39 of the bags have buttons but no zips. 21 of the bags have zips but no buttons. 23 of the bags have neither zips nor buttons.

Bags that have both zip and button

= Total number of bags - Number of bags with zips but no buttons - Number of bags with buttons but no zips - Number of bags with nor zips nor the buttons

= 140 - 21 - 39 - 23

= 57

Now, the number of bags that has zips will be the bags that only have zips and the number of bags that has zips and buttons. Therefore, the number of bags with zips is,

n = Bags that have both zip and button + Number of bags with zips but no buttons

   = 37 + 21

   = 78

Hence, the number of bags that zips on them is 78.

Learn more about Subtraction:

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4 0
2 years ago
Read 2 more answers
You own three different rings. You wear all three rings, but no two of the rings are on the same finger, nor are any of them on
Eddi Din [679]

Answer:

Therefore you can wear your rings in =336 ways

Step-by-step explanation:

Multiplication Law: If one occurs in x ways and second event occurs in y ways.Then the number of ways that two event occur in sequence is xy

Given that you have 3 different rings.

We have total 10 figures.

But you don't wear ring on your thumbs.

We have 2 thumbs.

So you can wear rings on (10-2) = 8 figures.

The ways of wearing of first ring is = 8

The ways of wearing of second ring is = 7

The ways of wearing of third ring is = 6

Therefore you can wear your rings in =(8×7×6)

                                                             =336 ways

4 0
3 years ago
How do I pick what subject I'm trying to get an answer for<br>​
Lyrx [107]
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6 0
3 years ago
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Consider a series circuit consisting of a resistor of R ohms, an inductor of L henries, and variable voltage source of V(t) volt
ser-zykov [4K]

Answer:

I(t)=\frac{1}{3}(1-e^{-30t})

Step-by-step explanation:

We are given that

\frac{dI}{dt}+\frac{R}{L}I=\frac{V(t)}{L}

R=150 ohm

L=5 H

V(t)=10 V

P=\frac{R}{L}=\frac{150}{5}=30

I.F=e^{\int Pdt}=e^{\int 30 dt}=e^{30 t}

I(t)\times I.F=\int e^{30 t}\times 10 dt+C

I(t)\times e^{30 t}=\frac{10}{30}e^{30 t}+C

I(t)=\frac{1}{3}+Ce^{-30 t}

I(0)=0

Substitute t=0

0=\frac{1}{3}+C

C=-\frac{1}{3}

Substitute the values

I(t)=\frac{1}{3}-\frac{1}{3}e^{-30 t}

I(t)=\frac{1}{3}(1-e^{-30t})

5 0
3 years ago
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