Write a number that has the same value as |5|

Leon drew AABC and ADEF so that ZA: LD, ZB: LE, AB = 4, and DE = 8.

yulyashka [42]

Answer:

A. similar - AA

there's two corresponding angle that are equal!

4 0

3 years ago

Perry observes opposite parallel wall of a room In how many lines do the planes containing the wall intersect

S_A_V [24]

Lady just stop
IDK know this

3 0

3 years ago

To repair a leak a plumber needs a pipe that is within 3/4 of an inch of 32 inches. He

Mrrafil [7]

Express all possible lengths for this scrap as a compound inequality will be L ≤ 24.

<h3>What is inequality?</h3>

Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.

To repair a leak a plumber needs a pipe that is within 3/4 of an inch of 32 inches.

⇒ 3/4 x 32

⇒ 24

He already has a 48-inch pipe.

Let the variable L represents the length of the extra (scrap) that is removed from the 48-inch pipe will be

Then express all possible lengths for this scrap as a compound inequality will be

L + 24 ≤ 48

L ≤ 48 - 24

L ≤ 24

More about the inequality link is given below.

brainly.com/question/19491153

#SPJ1

3 0

2 years ago

A cylindrical tank holds 352 cu. ft. of water. The height of the tank is 7 ft. Find the

Rzqust [24]

Answer:

0.3334 ft

Step-by-step explanation:

Measure the height and radius of the tank. The radius is the distance from the center of the tank to its outer edge. Another way to find the radius is to divide the diameter, or width, by two. Square the radius by multiplying the radius times itself and then multiply it by 3.1416, which is the constant pi.

Given height and volume: r = √(V / (π * h)),
Given height and lateral area: r = A_l / (2 * π * h),
Given height and total area: r = (√(h² + 2 * A / π) - h) / 2,
Given height and diagonal: r = √(h² + d²) / 2,
Given height and surface-area-to-volume ratio: r = 2 * h / (h * SA:V - 2),
Given volume and lateral area: r = 2 * V / A_l,
Given base area: r = √(A_b / (2 * π)),
Given lateral area and total area: r = √((A - A_l) / (2 * π)).

4 0

3 years ago

Dylan Rieder is a statistics student investigating whether athletes have better balance than non-athletes for a thesis project.

Kobotan [32]

Answer:

$t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457$

$p_v =P(t_{75}$

Comparing the p value with a significance level for example $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.

Step-by-step explanation:

Data given and notation

$\bar X_{A}=3.7$ represent the mean for athletes

$\bar X_{NA}=4.1$ represent the mean for non athletes

$s_{A}=1.1$ represent the sample standard deviation for athletes

$s_{NA}=1.3$ represent the sample standard deviation for non athletes

$n_{A}=32$ sample size for the group 2

$n_{NA}=45$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the population mean for athletes is lower than the population mean for non athletes, the system of hypothesis would be:

Null hypothesis: $\mu_{A}-\mu_{NA}\geq 0$

Alternative hypothesis: $\mu_{A} - \mu_{NA}< 0$

We don't have the population standard deviation's, we can apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{A}-\bar X_{NA})-\Delta}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{NA}}{n_{NA}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457$

P value

We need to find first the degrees of freedom given by:

$df=n_A +n_{NA}-2=32+45-2=75$

Since is a one left tailed test the p value would be:

$p_v =P(t_{75}$

Comparing the p value with a significance level for example $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.

5 0

3 years ago