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Drupady [299]
2 years ago
9

Solve the following system of equations by elimination​

Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
5 0

Answer:

y = -6

x = 1

Step-by-step explanation:

-x + 2y = -13

-x - 2y = 11

Sum the equations:

-x -x = -2x

+2y - 2y = 0

-13 + 11 = -2

then

-2x = -2

x = -2/-2

x = 1

from the first eq.

-x + 2y = -13

-1 + 2y = -13

2y = -13 + 1

2y = -12

y = -12/2

y = -6

check:

from the second eq.

-x -2y = 11

-1 -(2*-6) = 11

-1 -(-12) = 11

-1 + 12 = 11

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Find two complex numbers that have a sum of i10 a different of -4and a product of -29​
lianna [129]
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Step-by-step explanation:

   Let the complex numbers be a+ib\textrm{ and }c+id.

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(a+ib)(c+id)=(-2+5i)(2+5i)=-4-25=-29

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3 years ago
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6 0
4 years ago
Grade 7 Math 7. Can anyone help me answer this question? I want the correct answers. No, guessing.
algol13
Part one of your questions would be 1/20
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Please help me with this math question
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Answer:

C .56

Step-by-step explanation:

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Answer:

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4 0
2 years ago
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