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finlep [7]
2 years ago
13

Audrey is driving to a concert and needs to pay for parking. There is an automatic fee of $6 just to enter the parking lot, and

when she leaves the lot, she will have to pay an additional $2 for every hour she had her car in the lot. How much total money would Audrey have to pay for parking if she left her car in the lot for 5 hours? How much would Audrey have to pay if she left her car in the lot for tt hours?
Mathematics
1 answer:
Alborosie2 years ago
5 0

Answer:

a. $16

b. $26

Step-by-step explanation:

a. 6+2(5)= 16

b. im assuming tt means ten 6+2(10)=26

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9x-23=49 what is the second step in this equation?
ladessa [460]

Answer:

Divide both sides by 9.

Step-by-step explanation:

To find the second step of the equation, we actually have to solve parts of the equation until we get to step 2.

Step 1: Add 23 to both sides.

  • 9x - 23 + 23 = 49 + 23
  • 9x = 72

Step 2: Divide both sides by 9.

  • \frac{9x}{9} = \frac{72}{9}
  • x = 8

Therefore, the second step is divide both sides by 9.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

5 0
2 years ago
What are perfect numbers? Find the only 3examples below 500
liubo4ka [24]

The first two are 6 and 28. The factors of 6 add up to the same thing as 6.

Six

1 * 2 * 3 = 6

1 + 2 + 3 = 6

Twenty eight

1 + 2 +  4 + 7 + 14 = 28 (the multiplication is not the same as for 6).

Four hundred ninety Six

This one is kind of hard to believe

It is 16 * 31

1 + 2 + 4 + 8 + 16 + 248 + 124 + 62 + 31 = 496

4 0
3 years ago
6. Find the sum of whole number divisible by 3 and lies between 100 and 200.​
MatroZZZ [7]

Answer:

4950

Step-by-step explanation:

first find the smallest multiple of 3 thats >100, 3*33=99, so 3*34=102 is the smallest multiple of 3 >100.

next find the greatest multiple of 3 <200, 3*66=198 which is the greatest multiple of 3<200

34-66+1=number of terms=33. then find the average of the terms: 102+198/2=150. 150*33=4950. the answer should be 4950

3 0
3 years ago
Read 2 more answers
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serg [7]
The first one 2(x+1)
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