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2 years ago

Write an argument of any one

1 answer:

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<h3>I do think parallel universes exist. There are now some scientific theories that support the idea of parallel universes beyond our own. However, the multiverse theory remains one of the most controversial theories in science.Our universe is unimaginably big. Hundreds of billions, if not trillions, of galaxies(opens in new tab) spin through space, each containing billions or trillions of stars(opens in new tab). Some researchers studying models of the universe speculate that the universe's diameter could be 7 billion light-years(opens in new tab) across. Others think it could be infinite.

u might never know. It might or might not exist in conclusion. </h3>

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13. A lever does 5.0 J of work on a 0.10-kg ball bearing in a pinball machine. The ball's

shusha [124]

Answer:

The resulting speed of the ball is;

10 m/s

Explanation:

The given parameters are;

The amount of work done by the lever = 5.0 J

The mass of the ball on which the work is done, m = 0.10 kg

By the principle of conservation of energy, we have;

The work done by the lever = The kinetic energy. K.E., gained by the ball

The kinetic energy, K.E., is given by K.E. = 1/2·m·v²

Where, for the ball, we have;

m = The mass of the ball

v = The resulting speed of the ball

Therefore, by substituting the known values, we have;

The work done by the lever = 5.0 J = The kinetic energy. K.E., gained by the ball = 1/2 × m × v² = 1/2 × 0.10 kg × v²

∴ 5.0 J = 1/2 × 0.10 kg × v²

v² = 5.0 J/(1/2 × 0.10 kg) = 100 m²/s²

v = √(100 m²/s²) = 10 m/s

The resulting speed of the ball, v = 10 m/s.

6 0

3 years ago

What is the definition for relative motion

xeze [42]

Relative motion is the calculation of the motion of an object with regard to some other moving object.

7 0

3 years ago

Light wands are small tubes that can be used to give off light without electricity or fire.

miv72 [106K]

<span>c.the chemical energy of the fluids inside the wand</span>

4 0

3 years ago

Read 2 more answers

A roller coaster starts at the top of a hill of height h, goes down the hill, and does a circular loop of radius r before contin

jeka94

a) See free-body diagram in attachment

b) Net force in the y-direction: $F_y=mg+N$ [/tex]

c) The velocity at which the roller coaster will fall is $[tex]v=\sqrt{gr}$ [/tex]

d) The speed of the roller coaster must be 17.1 m/s

e) The roller coaster should start from a height of 90 m

f) The roller coaster should start from a height of 100 m

Explanation:

See the free-body diagram in attachment. There are only two forces acting on the roller coaster at the top of the loop:

The weight of the roller coaster, acting downward, indicated by $mg$ (where m is the mass of the roller coaster and g is the acceleration of gravity)
The normal reaction exerted by the track on the roller coaster, acting downward, and indicated with N

The two forces are represented in the diagram as two downward arrows (the length is not proportional to their magnitude, in this case)

Since there are only two forces acting on the roller coaster at the top of the loop, and both forces are acting downward, then we can write the vertical net force as follows (we take downward as positive direction):

$F_y = mg + N$

where

mg is the weight

N is the normal reaction

Since the roller coaster is in circular motion, this net force must be equal to the centripetal force, therefore

$m\frac{v^2}{r}=mg+N$

where v is the speed of the car at the top of the loop and r is the radius of the loop.

For this part of the problem, we start from the equation written in part b)

$m\frac{v^2}{r}=mg+N$

where the term on the left represents the centripetal force, and the terms on the right are the weight and the normal reaction.

We now re-arrange the equation making v (the speed) as the subject:

$v=\sqrt{gr+\frac{Nr}{m}}$

However, the velocity at which the roller coaster will fall is the velocity at which the normal reaction becomes zero (the roller coaster loses contact with the track), so when

N = 0

And as a result, the minimum velocity of the cart is

$v=\sqrt{gr}$

In this part, we are told that the radius of the loop is

r = 30 m

And the mass of the cart is

m = 50 kg

Moreover, the acceleration of gravity is

$g=9.8 m/s^2$

We said that the minimum velocity that the cart must have in order not to fall at the top is

$v=\sqrt{gr}$

And substituting, we find

$v=\sqrt{(9.8)(30)}=17.1 m/s$

According to the law of conservation of energy, the initial gravitational energy of the roller coaster at the starting point must be equal to the sum of the kinetic energy + gravitational potential energy at the top of the loop, therefore:

$mgh = \frac{1}{2}mv^2 + mg(2r)$

where

h is the initial height at the starting point

(2r) is the height of the roller coaster at the top of the loop

We can re-arrange the equation making h the subject,

$h=\frac{v^2}{2g}+2r$

And substituting the minimum speed of the cart,

$v=\sqrt{gr}$

this becomes

$h=r+2r=3r$

And since r = 30 m, we find

$h=3(30)=90 m$

In this case, 10% of the initial energy is lost during the motion of the roller coaster. We can rewrite the equation of the previous part as

$0.90mgh = \frac{1}{2}mv^2 + mg(2r)$

Because only 90% (0.90) of the initial energy is converted into useful energy (kinetic+potential) when the cart reaches the top of the loop.

Re-arranging the equation, this time we get

$h=\frac{\frac{v^2}{2g}+2r}{0.90}$

Again, by substituting $v=\sqrt{gr}$ , we get

$h=\frac{3r}{0.90}$

And therefore, the new initial height must be

$h=\frac{3(30)}{0.9}=100 m$

Learn more about kinetic and potential energy:

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#LearnwithBrainly

4 0

3 years ago

Which is a characteristic of projectile motion?

SVETLANKA909090 [29]

<h2>Right answer: It follows a curved path </h2>

The movement of a projectile is a movement in two dimensions (forming a curved path: a parabola shape) with <u>constant acceleration. </u>

A projectile is any body or object that is thrown or projected by means of some force and continues in motion by its own inertia. This means the only force that acts on it while in motion is <u>the acceleration of gravity</u> (in this case we are on Earth, so the gravity value is $9.8\frac{m}{s^{2}}$ ).

Where gravity influences the <u>vertical movement</u> of the projectile, while <u>the horizontal movement</u> of the projectile is the result of the tendency of any object to remain in motion at a constant speed (according to Newton's 1st law of motion sometimes called Law of Inertia).

The other options are <u>incorrect</u> because are <u>false</u>:

-The forward motion negates air resistance: There is always at least a small percent of air resistance, as long as that movement is done on Earth.

-It has variable acceleration: In projectile motion acceleration is constant (gravity acceleration) .

-It is unaffected by gravity: The only force that acts on the projectile is due gravity.

5 0

3 years ago

Read 2 more answers