Answer:
1456 N
Explanation:
Given that
Frequency of the piano, f = 27.5 Hz
Entire length of the string, l = 2 m
Mass of the piano, m = 400 g
Length of the vibrating section of the string, L = 1.9 m
Tension needed, T = ?
The formula for the tension is represented as
T = 4mL²f²/ l, where
T = tension
m = mass
L = length of vibrating part
F = frequency
l = length of the whole part
If we substitute and apply the values we have Fri. The question, we would have
T = (4 * 0.4 * 1.9² * 27.5²) / 2
T = 4368.1 / 2
T = 1456 N
Thus, we could conclude that the tension needed to tune the string properly is 1456 N
<u>Answer:</u>
The time taken for the ball to hit the floor as 1.02 seconds
<u>Explanation:</u>
As per the given question, the ball leaves at a speed from the table with an initial velocity of 10 m/s, we have the equation
where Vf represents the final velocity
Vi represents the initial velocity
a represents the acceleration and
t represents the time
after rearranging
= 1.022 seconds
The frequency of a wave is equal to the linear speed divided the wavelength. so in equation form.
f = v / l
so the wavlength
l = v / f
where f is the frequency
v iss the linear speed
l is the wavelength
l = ( 5100 m/s ) / ( 2.2 Mhz ) ( 10^6 hz / 1 Mhz )
f = 0.0023 m
f = 2.3 mm
Answer:
After the colision, the stationary electron's momentum is given as:
P = 2.7328 x 10^(-25) kg m/s
The direction of momentum is the same as the direction of velocity of the electron.
Explanation:
In an Isolated system, when an object moving at some velocity v collides head on with a stationary object of equal mass. There velocities are exchanged.
This means that the first electron will become stationary and the electron which was stationary initially will start moving at a velocity of 3*10^(5)m/s in the same direction as the first electron.
Post collision momentum of the stationary electron:
V = 3 x 10^5 m/s
m = 9.1093 x 10^(-31) kg
Momentum = P = mV = 9.1093 x 10^(-31) x 3 x 10^5
P = 2.7328 x 10^(-25) kg m/s
The direction of momentum is the same as the velocity of the electron.
