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3 years ago

How do we know what is inside of Earth ?

Physics

1 answer:

Maslowich3 years ago

5 0

Answer:

Most of what we know about the interior of the Earth comes from the study of seismic waves from earthquakes. Seismic waves from large earthquakes pass throughout the Earth. These waves contain vital information about the internal structure of the Earth.

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PLZZZZ HELPPPPPP MEEEEEE!!!!!! ASAP!!! ILL GIVE 20 POINTS AND BRAINLIEST!!!

Mama L [17]

Answer:

the correct one is B ₊₁e

Explanation:

In the radioactive emission process there are three fundamental types, enision of alpha particles, emission of beta rays and emission of high energy photons.

In beta particle emission processes, a neutron decomposes, emitting an electron and an antineutrino, so the mass number of the nucleus does not change, but the atomic number increases by one unit.

Another possibility is the emission of a positron (positive charge) plus a neutrino, in this case the atomic mass remains constant and the atomic number decreases by one unit.

The second beta emission process if it describes the situation presented, when reviewing the answers the correct one is B

5 0

3 years ago

You push the ball with aforce of 22.8N which induces a -2.3N frictional force. What is the net force while you push?

inna [77]

The net force is 22.8-2.3 or 20.5 N

5 0

3 years ago

Distance v. Time

Allushta [10]

Answer:

(m)

2 ( s )

Explanation:

ok...........

3 0

3 years ago

Ball 1, with a mass of 100 g and traveling at 10 m/s, collides head-on with ball 2, which has a mass of 300 g and is initially a

qaws [65]

There is 4000 balls in the earth of the world why is that so hard for you

5 0

2 years ago

An emf is induced in a conducting loop of wire 1.22 m long as its shape is changed from square to circular. Find the average mag

Afina-wow [57]

Answer:

The induced emf in the loop is $7.35\times 10^{-4}\ V$

Explanation:

Given that,

Length of the wire, L = 1.22 m

It changes its shape is changed from square to circular. Then the side of square be its circumference, 4a = L

4a = 1.22

a = 0.305 m

Area of square, $A=a^2=(0.305)^2=0.0930\ m^2$

Circumference of the loop,

$C=2\pi r=L\\\\r=\dfrac{L}{2\pi}\\\\r=\dfrac{1.22}{2\pi}=0.194\ m$

Area of circle,

$A'=\pi r^2\\A'=\pi (0.194)^2\\\\A'=0.118\ m^2$

The induced emf is given by :

$\epsilon=\dfrac{\d\phi}{dt}\\\\\epsilon=\dfrac{\d(BA)}{dt}\\\\\epsilon=B\dfrac{A'-A}{t}\\\\\epsilon=0.125 \times \dfrac{0.118-0.0930}{4.25}\\\\\epsilon=7.35\times 10^{-4}\ V$

So, the induced emf in the loop is $7.35\times 10^{-4}\ V$

8 0

3 years ago