Question

Please help with this answe i do not how to to do it it

Answer 1

Answer:

1.20 M (3 s.f.)

Explanation:

In this question, we are trying to find the concentration of KCl after dilution. Note that the number of moles of KCl does not change.

$g \div \frac{g}{mol} = g \times \frac{mol}{g} = mol$

Number of moles of KCl

= 44.7 ÷74.55

= 0.59960 mol (5 s.f.)

New volume

= 500 mL

= (500 ÷1000) L

= 0.5 L

Concentration after dilution

= 0.59960 ÷0.5

= 1.1992 mol/L

= 1.20 M (3 s.f.)

* M is the symbol for Molarity, which is also equal to mol/L