The dissociation of calcium carbonate, CaCO3, to simpler compounds can be expressed as,
CaCO3 --> CaO + CO2
The precipitate is CaO and its amount is calculated through the difference which will give us the answer of 5.6 g.
To calculate the average mass of the element, we take the summation of the product of the isotope and the percent abundance. We calculate as follows:
Average atomic mass = .374 ( 184.953 amu ) + .626 ( <span>186.958 amu ) = 186.208 amu
Hope this answers the question. Have a nice day.</span>
1.07 mol would be your answer
Molar mass K₂SO₄ = 174.259 g/mol
moles
hope this helps!
