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AveGali [126]
3 years ago
15

If you have 90L of water, what is the volume?

Chemistry
1 answer:
Artist 52 [7]3 years ago
7 0

Answer:

900

Explanation:

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Why is water considered "sticky"? What does that mean?
dmitriy555 [2]

Answer:

Explanation:

Ya que las cargas eléctricas opuestas se atraen, las moléculas de agua tienden a atraerse unas a otras, haciendo el agua "pegajosa," como lo muestra el diagrama del lado derecho. Cuando las moléculas de agua se atraen unas a otras, se unen. Esta es la razón del porqué se forman las gotas

8 0
3 years ago
Read 2 more answers
In which of the following reactions will Kc= Kp?A) 4 NH3(g) + 3 O2(g) ⇌2 N2(g) + 6 H2O(g)B) 2 SO3(g) + 2 NO(g) ⇌2 SO2(g) + 2 NO2
inessss [21]

Answer: 2SO_3(g)+2NO(g)\rightleftharpoons 2SO_2(g)+2NO_2(g)

Explanation:

Relation of K_p with K_c is given by the formula:

K_p=K_c(RT)^{\Delta ng}

where,

K_p = equilibrium constant in terms of partial pressure

K_c = equilibrium constant in terms of concentration

R = Gas constant

T = temperature

\Delta n_g = change in number of moles of gas particles = n_{products}-n_{reactants}

K_p=K_c when \Delta n_g = 0

a) 4NH_3(g)+3O_2(g)\rightleftharpoons 2N_2(g)+6H_2O(g)

\Delta n_g = change in number of moles of gas particles = 8-7=1

b) 2SO_3(g)+2NO(g)\rightleftharpoons 2SO_2(g)+2NO_2(g)

\Delta n_g = change in number of moles of gas particles = 4-4=0

c) 4N_2(g)+2O_2(g)\rightleftharpoons 4N_2O(g)

\Delta n_g = change in number of moles of gas particles = 4-6=-2

d) 6SO_2(g)+3O_2(g)\rightleftharpoons 6SO_3(g)

\Delta n_g = change in number of moles of gas particles = 6-9=-3

Thus for reaction ,2SO_3(g)+2NO(g)\rightleftharpoons 2SO_2(g)+2NO_2(g) , K_p=K_c as \Delta n_g = 0

5 0
3 years ago
How many moles in 5 grams of gold
Ainat [17]
There is 0.02538502095915 Moles in 5 grams of gold.
8 0
4 years ago
Read 2 more answers
Which correctly describes particles of a substance in the gas phase?
astraxan [27]
Solid= Connected and Concentrated and Bound Together.

Liquid= Not bound but free flowing, less concentrated.

Gas= Spaced out and not concentrated, floating freely through space.
5 0
4 years ago
Read 2 more answers
If 35.5 mL of 0.23 M HCl is required to completely neutralize 20.0 mL of NH3, what is the concentration of the NH3 solution? Sho
V125BC [204]
NH3 is neutralised by the equation:

HCL + NH3 -> NH4CL

In this equation there is a one to one relationship in terms of the number of moles of each reactant. I.e. To neutralise 1 mole of NH3 we require 1 mole of HCL.

To calculate the concentration of NH3 required, we must first calculate the number of moles of HCL used.

volume HCL = 35.5mL = 0.0355 litres 
concentration HCL = 0.23M = 0.23 mole/litre 
Note that the term "M" for concentration simply means moles/litre
number moles = concentration x volume
number moles HCL = 0.0355 x 0.23 = 0.008165 moles HCL
based on the equation, we know the number of moles of NH3 must be the same

So, 
moles NH3, n = 0.008165
volume NH3, v = 20.0mL = 0.020 litres
n = c x v
c = n / v
c = 0.008165 / 0.020
=0.41
i.e. the concentration of NH3 would be 0.41 moles/litre or 0.41M

This intuitively makes sense because there is less volume of NH3 required to be neturalised, in a one-to-one mole relationship. So the concentration of NH3 would need to be higher than that of HCL.

6 0
3 years ago
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