Explanation:
<u>According to Newton's second law F=ma.</u>
<u>According to Newton's second law F=ma.For first object</u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)</u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)For second object</u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)For second objectand 2F=m </u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)For second objectand 2F=m ′</u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)For second objectand 2F=m ′ ×5a..........(2)</u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)For second objectand 2F=m ′ ×5a..........(2)Solving these two equations, we get</u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)For second objectand 2F=m ′ ×5a..........(2)Solving these two equations, we get⟹ 2m×a=m </u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)For second objectand 2F=m ′ ×5a..........(2)Solving these two equations, we get⟹ 2m×a=m ′</u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)For second objectand 2F=m ′ ×5a..........(2)Solving these two equations, we get⟹ 2m×a=m ′ ×5a</u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)For second objectand 2F=m ′ ×5a..........(2)Solving these two equations, we get⟹ 2m×a=m ′ ×5a⟹m </u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)For second objectand 2F=m ′ ×5a..........(2)Solving these two equations, we get⟹ 2m×a=m ′ ×5a⟹m 2</u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)For second objectand 2F=m ′ ×5a..........(2)Solving these two equations, we get⟹ 2m×a=m ′ ×5a⟹m 2</u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)For second objectand 2F=m ′ ×5a..........(2)Solving these two equations, we get⟹ 2m×a=m ′ ×5a⟹m 2 = </u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)For second objectand 2F=m ′ ×5a..........(2)Solving these two equations, we get⟹ 2m×a=m ′ ×5a⟹m 2 = 5</u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)For second objectand 2F=m ′ ×5a..........(2)Solving these two equations, we get⟹ 2m×a=m ′ ×5a⟹m 2 = 52m</u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)For second objectand 2F=m ′ ×5a..........(2)Solving these two equations, we get⟹ 2m×a=m ′ ×5a⟹m 2 = 52m</u>
<u>According to Newton's second law F=ma.For first objectF=m×a ...........(1)For second objectand 2F=m ′ ×5a..........(2)Solving these two equations, we get⟹ 2m×a=m ′ ×5a⟹m 2 = 52m </u>