Answer:
Explanation:
plate separation = 2.3 x 10⁻³ m
capacity C₁ = ε A / d
= ε A / 2.3 x 10⁻³
C₂ = ε A / 1.15 x 10⁻³
= 
a ) when charge remains constant
energy = 
q is charge and C is capacity
energy stored initially E₁= 
energy stored finally E₂ = 
= 
= 
= 
= 4.19 J
b )
In this case potential diff remains constant
energy of capacitor = 1/2 C V²
energy is proportional to capacity as V is constant .


= 16.76 .
Answer:
Distance between the charges, r = 0.8 meters
Explanation:
Given that,
Charge 1, 
Charge 2, 
Repulsive force between charges, F = 0.66 N
Let r is the distance between charges. The formula for the electrostatic force is given by :


r = 0.8009 meters
or
r = 0.8 meters
So, the distance between the charges i 0.8 meters. Hence, this is the required solution.