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kkurt [141]
3 years ago
13

Desert sand is very hot in the day and very cool at night. what does this indicate about its specific heat capacity?

Physics
1 answer:
expeople1 [14]3 years ago
6 0
That the climate changes during the day and night high to low
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A 2.00 m wave has a frequency of 686 Hz. What is the speed of the wave?
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Wave speed = frequency * wavelength
Wave speed = 686 * 2.00
Wave speed = 1,372 (m/s)
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. A projectile is launched from a cliff 100m above level ground with a velocity of 30m/s at an
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How to find the maximum height of a projectile?

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if α = 45°, then the equation may be written as: ...

if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion.

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Write true if the statement is false change the underlined word to make the statement true. Write our answers on a separate shee
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Explanation:

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How does activity on the Sun affect natural phenomena on Earth?
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Answer and Explanation:

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Orchestra instruments are commonly tuned to match an A-note played by the principal oboe. The Baltimore Symphony Orchestra tunes
Nina [5.8K]

Answer:

Δλ = 3*10⁻³ m.

Explanation:

  • At any wave, there exists a fixed relationship between the speed of  the wave, the wavelength, and the frequency, as follows:

       v = \lambda* f  (1)

       where v is the speed, λ is the wavelength and f is the frequency.

  • Rearranging terms, we can get λ from the other two parameters, as follows:

       \lambda = \frac{v}{f}  (2)

  • Since v is constant for sound at 343 m/s, we can find the different wavelengths at different frequencies, as follows:

        \lambda_{1} =\frac{v}{f_{1}} = \frac{343m/s}{440(1/s)} = 0.779 m  (3)

        \lambda_{2} =\frac{v}{f_{2}} = \frac{343m/s}{442(1/s)} = 0.776 m  (4)

  • The difference between both wavelengths, is just the difference between (3) and (4):

       \Delta \lambda = \lambda_{1} - \lambda_{2} = 0.779 m - 0.776m = 3e-3 m (5)

       ⇒ Δλ = 3*10⁻³ m.

6 0
3 years ago
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