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mrs_skeptik [129]
3 years ago
14

Technician A says that magnetic lines of force can be seen by placing iron filings on a piece of paper and then holding them ove

r a magnet. Technician B says that the effects of magnetic lines of force can be seen using a compass. Which technician is correct?
Physics
2 answers:
aev [14]3 years ago
5 0

Answer:

Technician A is correct

Magnetic lines of force can be seen by placing iron filings on a piece of paper and then holding them over a magnet.

Explanation:

As we know that the magnetic field lines are always originated out from the North pole of magnet and then terminate at south pole of the magnet

Here we know that when magnetic material aligns itself in the direction of external magnetic field

So here when we put the iron filings on the cardboard and then place a magnet near it then all the iron filing will align itself in the direction of the magnetic field

Now if we place a compass near the magnet then it will aligns itself in the tangential direction of the magnetic field at the same position

So here we can say that Technician A is correct

Eva8 [605]3 years ago
4 0

Answer:

Both A and B are correct

Explanation:

  • Magnetic line of force can be seen by placing iron fillings on a piece of paper and then hold a magnet over them, the iron fillings align themselves in the magnetic field of the magnetic along the line of forces thus showing the loops of the magnetic line of forces.
  • Also, we know that unlike poles attract where as like poles repel each other. This fact can be proved when we hang a bar magnet it aligns itself in the North-South direction because of the the magnetic field due to the alignment of the geographical North-South poles and the poles of the bar magnet and the compass works the same way.

Thus both the technicians are correct.

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A disoriented physics professor drives 3.22 km north, then 4.75 km west, then 1.90 km south. find the magnitude and direction of
Andre45 [30]

It can be noted that the directions west and north are perpendicular to each other. hence we can use the right angle formula for calculating total distance in these directions. Also South is just negative north. This technique is called euclidean distance norm. It is the basis of Cartesian coordinate system.

Total distance = 3.22 N + 4.75 W +1.90  S

= 1.32 N + 4.75 W

D = \sqrt{N^2 + W^2}

D = 4.93 Km

direction = atan(N/W) = 15.53 deg north of west

7 0
3 years ago
What is the symbol name?
murzikaleks [220]

Answer:

cell

Explanation:

here are all the symbols-

hope this helps, take care and stay safe

7 0
3 years ago
If C is 1kg and D is 100kg, and the initial velocities of both balls are 5m/s, how would the magnitude of the forces exerted by
kupik [55]

Answer:

Explanation:

The forces exerted by each mass is best understood in terms of their momentum.

Momentum is a sort of compelling force or impulse. It is given as:

                  Momentum  =  mass x velocity

Let us consider the momentum of the balls;

Substance C;

    Mass  = 1kg

     Velocity  = 5m/s

    Momentum of C = 1 x 5  = 5kgm/s

Substance D:

      Mass  = 100kg

      Velocity  = 5m/s

     Momentum of D  = 100kg x 5m/s  = 500kgm/s

Body D has a higher momentum compared to Body C. This suggests that body D will exert a higher force than C when they collide.

The higher the momentum, the more the force of impact it has.

3 0
3 years ago
`i have a sealed cylinder sitting in my lab that contains 1,000.0 ml of gas. if i compress the cylinder and change the volume to
marin [14]
Because the temperature remains constant, we can apply Boyle's Law which states that 
pV = constant
where
p = pressure
V = volume

Define the two states of the gas.

State 1
Pressure = p₁
Volume = 1000 ml

State 2
Pressure = p₂
Volume = 500 ml

Apply Boyle's law.
1000p₁ = 500p₂
2 = p₂/p₁

By halving the volume, the pressure doubles.

Answer:
The pressure increases by a factor of 2.

7 0
3 years ago
A piece of aluminum has a volume of 1.50 10-3 m3. the coefficient of volume expansion for aluminum is β = 69 ✕ 10-6 (°c)-1. the
Alex17521 [72]

Answer:

W = 3.12 J

Explanation:

Given the volume is 1.50*10^-3  m^3 and the coefficient of volume for aluminum is β = 69*10^-6 (°C)^-1. The temperature rises from 22°C to 320°C. The difference in temperature is 320 - 22 = 298°C, so ΔT = 298°C. To reiterate our known values we have:

β = 69*10^-6 (°C)^-1       V = 1.50*10^-3  m^3       ΔT = 298°C

So we can plug into the thermal expansion equation to find ΔV which is how much the volume expanded (I'll use d instead of Δ because of format):

dV = \beta V_{0} dT\\dV = (69*10^{-6})( C)^{-1} * (1.50*10^{-3})m^{3} * (298)C\\dV = 3.0843*10^-5

So ΔV = 3.0843*10^-5 m^3

Now we have ΔV, next we have to solve for the work done by thermal expansion. The air pressure is 1.01 * 10^5 Pa

To get work, multiply the air pressure and the volume change.

W = P * dV = (1.01 * 10^5)Pa * (3.0843*10^{-5})m^3\\W = 3.115143J

W = 3.12 J

Hope this helps!

4 0
3 years ago
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