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natka813 [3]
3 years ago
9

A piece of transparent meterial which has one or two spherical surfaces is called​

Physics
1 answer:
Iteru [2.4K]3 years ago
4 0

Answer:

Lens

Explanation:

Lenses fit this description.

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Technician A states that accidents avoidance is an additional feature on some electronic stability control systems. Technician B
Julli [10]

Answer:

Both A and B are right.

Explanation:

-Electronic Stability Control (ESC) helps drivers to avoid crashes by reducing the danger of skidding, or losing control as a result of over-steering. The ESC activates in the instant that a driver loses control.

-The Sway Control is an added feature that helps eliminate trailer sway and takes action when necessary via the electric brake system, to maintain road position.

5 0
3 years ago
A piece of plastic has a net charge of +9.9 μC. How many more protons than electrons does this piece of plastic have? (e = 1.60
Leto [7]

Answer:

The number of protons 6.19 more than electron.

Explanation:

Given that,

Charge Q=+9.9\times10^{-6}\ C

We know that,

formula of charge

Q = nc

Where,

Q = total charge

n = number of protons

e = charge of electron

Put the value into the formula

n = \dfrac{Q}{e}

n=\dfrac{9.9\times10^{-6}}{1.6\times10^{-19}}

n=6.1875\times10^{13}\ C

According to statement of question

Divide the answer by 10^{13}

n=\dfrac{6.1875\times10^{13}}{10^{13}}

n=6.19\ C

Hence, The number of protons 6.19 more than electron.

6 0
3 years ago
A 1.50-kg iron horseshoe initially at 550°C is dropped into a bucket containing 25.0 kg of water at 20.0°C. What is the final te
Ber [7]

Answer:

Te =  23.4 °C

Explanation:

Given:-

- The mass of iron horseshoe, m = 1.50 kg

- The initial temperature of horseshoe, Ti_h = 550°C

- The specific heat capacity of iron, ci = 448 J/kgC

- The mass of water, M = 25 kg

- The initial temperature of water, Ti_w = 20°C

- The specific heat capacity of water, cw = 4186 J/kgC

Find:-

What is the final temperature of the water–horseshoe system?

Solution:-

- The interaction of horseshoe and water at their respective initial temperatures will obey the Zeroth and First Law of thermodynamics. The horseshoe at higher temperature comes in thermal equilibrium with the water at lower temperature. We denote the equilibrium temperature as (Te) and apply the First Law of thermodynamics on the system:

                             m*ci*( Ti_h - Te) = M*cw*( Te - Ti_w )

- Solve for (Te):

                             m*ci*( Ti_h ) + M*cw*( Ti_w ) = Te* (m*ci + M*cw )

                             Te = [ m*ci*( Ti_h ) + M*cw*( Ti_w ) ] / [ m*ci + M*cw ]

- Plug in the values and evaluate (Te):

                             Te = [1.5*448*550 + 25*4186*20 ] / [ 1.5*448 + 25*4186 ]

                             Te = 2462600 / 105322

                             Te =  23.4 °C    

7 0
3 years ago
Read 2 more answers
How do particles move differently in transverse waves and in surface water waves?
elixir [45]
The particles always move parallel and perpendicular to the waves. The waves which are in the water moves a circle. Both up and down and back and forth.

Good luck :)
3 0
3 years ago
A charge of Q is fixed in space. A second charge of q was first placed at a distance r1 away from Q. Then it was moved along a s
topjm [15]

Answer:

\Delta U = \frac{Qq}{4\pi\epsilon_0}(\frac{1}{r_2^2}-\frac{1}{r_1^2})

Explanation:

The electrostatic potential energy is given by the following formula

U = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2}

Now, we will apply this formula to both cases:

U_1 = \frac{1}{4\pi\epsilon_0}\frac{Qq}{r_1^2}\\U_2 = \frac{1}{4\pi\epsilon_0}\frac{Qq}{r_2^2}

So, the change in the potential energy is

\Delta U = U_2 - U_1 = \frac{Qq}{4\pi\epsilon_0}(\frac{1}{r_2^2}-\frac{1}{r_1^2})

7 0
3 years ago
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