Answer:
Step-by-step explanation:
2x^2-6x+10=0
2(x^2-3x)+10=0
2(x-(3/2))^2-9/4)+10=0
2(x-(3/2))^2+10-9/2=0
2(x-(3/2))^2+(20-9)/2=0
2(x-(3/2))^2+11/2=0
2(x-(3/2))^2=-11/2
square is always positive so there is no solution
The value of a=9,b=3 and c=1
Step-by-step explanation:
The graph shown is for function f(x)
The given function is f(x)=
Table says,
X Y
-2 a
1 b
0 c
1 (1/3)
2 (1/9)
To find value of a:
From table, for output value a, input value, x=(-2)
we can write f(-2)=a
Therefore,
f(x)=
f(-2)=
a=
a=
a=9
To find value of b:
From table, for output value a, input value, x=(-1)
we can write f(-1)=b
Therefore,
f(x)=
f(-1)=
b=
b=
b=3
To find value of c:
From table, for output value a, input value, x=(0)
we can write f(0)=c
Therefore,
f(x)=
f(0)=
c=
c=1
Answer:
Joni is not correct because she used the simple interest rate formula, not the compound interest rate formula. She will have $231.53.
Step-by-step explanation:
I already took the test
Option C:
The value of m is 4.
Solution:
Given data:
AB = 4m – 15
BC = 5m –6
AC = 15
<u>To find the value of m:</u>
Using segment addition postulate,
AB + BC = AC
4m – 15 + 5m –6 = 15
Arrange the like terms together.
4m + 5m – 15 – 6 = 15
9m – 21 = 15
Add 21 on both sides of the equation,
9m = 36
Divide by 9 on both sides of the equation.
m = 4
The value of m is 4.
Option C is the correct answer.
I think the third one is the answer
