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2 years ago

Which of the following is a solution of x^2 + 2x + 8?

1 answer:

5 0

X^2 + 2x + 8 = 0
x^2 + 2x = -8
x^2 + 2x + 1 = -8 + 1
(x + 1)^2 = -7
x + 1 = (+-) sqrt -7
x = -1 (+-) sqrt -7

solution is : x = -1 + i * sqrt 7

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IF P(A)=1/3, P(B)=2/5, and P(AuB)=3/5, what is P(A^B)?

Bumek [7]

The probability of the union of two events is the sum of their probability, minus the probability of their interserction:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

If we plug the known values into this formula, we have

$\dfrac{3}{5} = \dfrac{1}{3} + \dfrac{2}{5} - P(A\cap B)$

From which we can deduce

$P(A\cap B) = \dfrac{1}{3} + \dfrac{2}{5} - \dfrac{3}{5} = \dfrac{2}{15}$

So, the probability of $A \setminus B$ is a bit less than $P(A)$ , we have to take away all events that belong to B as well:

$P(A \setminus B) = P(A) - P(A\cap B) = \dfrac{1}{3} - \dfrac{2}{15} = \dfrac{1}{5}$

3 0

3 years ago

Find the Area of the composite shape shown below:

spin [16.1K]

Answer:

104 ft

Step-by-step explanation:

6 x 4 = 24

16 x 8 = 128

128 - 24 = 104 ft

7 0

2 years ago

How to find the slope and y-intercept using a graph??????????

svlad2 [7]

The y-intercept is where on the graph the line is intersecting the y=axis. Slope is in the form y=mx+b (b=y-intercept, mx=how far up and over.)

6 0

2 years ago

Read 2 more answers

Someone please help I really appreciate it

Alex_Xolod [135]

So you have to find the relationship between the pumpkin diameter (y) and the number of weeks passed (x) in a table, lets do it taking into account that the equation modeling such behaviour is:
y = 2x + 6, where x is the number of weeks and plus original 6 cm
x y
week diameter
0 6
1 8
3 12
5 16
10 26
substitute the x and y values in the equation to see how they fit into it

5 0

2 years ago

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The scatter plot shows a correlation between the years and the rainfall in centimeters in Tennessee.

nataly862011 [7]

Answer:

Step-by-step explanation:

The actual values are shown on the given graph as blue points.

The line of regression is shown on the given graph as the red line.

From inspection of the graph, in the year 2000 the actual rainfall was 43 cm, shown by point (2000, 43). It appears that the regression line is at y = 50 when x is the year 2000.

⇒ Difference = 50 - 43 = 7 cm

In 2000, the actual rainfall was 7 centimeters below what the model predicts.

From inspection of the graph, in the year 2003 the actual rainfall was 44 cm, shown by point (2003, 40). It appears that the regression line is at y = 40 when x is the year 2003.

⇒ Difference = 44 - 40 = 4 cm

In 2003, the actual rainfall was 4 centimeters above what the model predicts.

3 0

1 year ago