Question

When dividing the polynomial using synthetic division, which of the following setup boxes would be used?

Answer 1

The setup boxes in the synthetic division are (b)

How to determine the setup boxes?

The dividend is given as:

x^3 + 4x^2 + x - 6

The divisor is given as:

x - 2

Set the divisor to 0

x - 2 = 0

Solve for x

x = 2

Remove the variables in the dividend

1 + 4 + 1 - 6

Remove the arithmetic signs

1  4  1 - 6

So, the setup is:

2 | 1  4  1 - 6

Hence, the setup boxes are (b)

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