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olya-2409 [2.1K]
3 years ago
14

A stuffed toy with a mass of 0.900 kilograms sits on the edge of a bed at a height of 0.830 if the toy falls off the bed what wi

ll it mechanical energy be at a height of 0.500 meters
Physics
1 answer:
Olenka [21]3 years ago
8 0
Mechanical energy (ME) is the sum of potential energy (PE) and kinetic energy (KE). When the toy falls, energy is converted from PE to KE, but by conservation of energy, ME (and therefore PE+KE) will remain the same.

Therefore, ME at 0.500 m is the same as ME at 0.830 m (the starting point). It's easier to calculate ME at the starting point because its just PE we need to worry about (but if we wanted to we could calculate the instantaneous PE and KE at 0.500 m too and add them to get the same answer).

At the start:

ME = PE = mgh
ME = 0.900 (9.8) (0.830)
ME = 7.32 J
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How are magnetic poles and electrical charges similar? A. Their same forces repel each other, and their opposite forces attract
melomori [17]

Answer:

A. Their same forces repel each other, and their opposite forces attract each other.

Explanation:

As we know by the property of electric charge that similar charges repel each other and opposite charges attracts each other

So here we have similar situation in magnets also

Two similar poles or like poles of magnet i.e. North - North poles or South - South poles always repel each other

And also we can see that opposite poles of magnet each other i.e. North pole and south pole always attract each other.

SO here correct answer is

A. Their same forces repel each other, and their opposite forces attract each other.

8 0
3 years ago
Помогите плз!
Softa [21]

Все написано в скобках правильно

3 0
3 years ago
You then measure Polly's internal temperature to be 13oC, which is quite a drop from the normal human body temperature of 37oC.
ankoles [38]

Answer:

The specific heat is 3.47222 J/kg°C.

Explanation:

Given that,

Temperature = 13°C

Temperature = 37°C

Mass = 60 Kg

Energy = 5000 J

We need to calculate the specific heat

Using formula of energy

Q= mc\Delta T

c =\dfrac{Q}{m\Delta T}

Put the value into the formula

c=\dfrac{5000}{60\times(37-13)}

c=3.47222\ J/kg^{\circ}C

Hence, The specific heat is 3.47222 J/kg°C.

5 0
3 years ago
An object of mass 5 m is lifted to a height of 5 h above the floor. What is the potential energy the object gained in this proce
Gekata [30.6K]

Answer:

Potential energy, E = 25 mgh

Explanation:

Given that,

Mass of the object, m = 5 m

It is lifted to a height of, h = 5 h

It is required to find the potential energy gained by the object. It is given by the product of object's mass, acceleration due to gravity and heigh above ground. It is given by :

E=m\times g\times h

E=5\ m\times g\times 5\ h

E = 25 mgh

So, the potential energy gained by the object is (25 mgh). Hence, this is the required solution.

7 0
3 years ago
An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 28.9
Lera25 [3.4K]

Answer:

a = 0.016 m/s^2

the airplane's acceleration is 0.016 m/s^2

Explanation:

Applying the equation of motion;

v^2 = u^2 + 2as ........1

Where;

v = final velocity = 47.5 m/s

u = initial velocity = 28.9 m/s

a = acceleration

s = displacement = 45300m

From equation 1, making a the subject of formula;

v^2 = u^2 + 2as

2as = v^2 - u^2

a = (v^2 - u^2)/2s

Substituting the given values;

a = (47.5^2 - 28.9^2)/(2×45300)

a = 0.015684768211 m/s^2

a = 0.016 m/s^2

the airplane's acceleration is 0.016 m/s^2

5 0
3 years ago
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