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mina [271]
2 years ago
5

A slice of pizza has 500 kcal. If we could burn the pizza and use all the heat to warm a 50-L container of cold water, what woul

d be the approximate increase in the temperature of the water?
Physics
2 answers:
JulsSmile [24]2 years ago
6 0

Answer:

D

Explanation:

topjm [15]2 years ago
4 0

Answer:

increase in temperature of water is 10° C

Explanation:

Given data

pizza = 500 kcal = 500000 calories

cold water = 50 L

to find out

increase in temperature of water

solution

we know heat formula that is

heat = m × specific heat × Δt

here m is mass = 50000 gram and Δt is change in temperature

and specific heat = 1 cal / gram C

so put here all value and find Δt

500000 = 50000 × 1  × Δt

Δt = 10° C

so increase in temperature of water is 10° C

You might be interested in
the train accelerates from 30 km/h to 45 km/h in 15 secs. a. find its acceleration. b. distance it travels during this time ...
Sonbull [250]
Acceleration = v-u/t
= (45-30)/15
= 1 km/h


Distance = ut + 1/2 at^2
s = [30 x 15]  + 1/2 x 1 x 15^2 
= 562.5 km

Hope this helps

3 0
3 years ago
Read 2 more answers
A lead mass is heated and placed in a foam cup calorimeter containing 50.0 ml of water at 18.0°c. the water reaches a temperatur
maria [59]
Assuming that there is no heat loss, and the cup is perfectly insulated, all of the energy lost by the lead will be absorbed by the water.
The heat absorbed is given by:
Energy = mass * specific heat capacity * change in temperature
The specific heat capacity of water is 4.18 joules per gram.

In order to compute the mass, we will use the fact that the density of water is one gram per milliliter. Therefore, the mass of water is 50 grams.

Now,
Q = 50 * 4.18 * (20 - 18)
Q = 418 J

418 Joules of energy were released by the lead.
4 0
3 years ago
Consider the reaction data. A ⟶ products T ( K ) k ( s − 1 ) 225 0.385 525 0.635 What two points should be plotted to graphicall
lutik1710 [3]

Answer:

Plot ln K vs 1/T

(a) -0.5004; (b) 0.002 539 K⁻¹; (c) -197.1 K⁻¹; (d) 1.64 kJ/mol

Explanation:

This is an example of the Arrhenius equation:

k = Ae^{-E_{a}/RT}\\\text{Take the ln of each side}\\\ln k = \ln A - \dfrac{E_{a}}{RT}\\\\\text{We can rearrange this to give}\\\ln k = - \dfrac{E_{a}}{R}\dfrac{1}{T} + \ln A\\\\y = mx + b

Thus, if we plot ln k vs 1/T, we should get a straight line with slope = -Eₐ/R and a y-intercept = lnA

Data:

\begin{array}{cccc}\textbf{k/s}\mathbf{^{-1}} &\mathbf{\ln k} & \textbf{T/K} & \mathbf{1/T(K^{-1})}\\0.285 & -0.9545 & 225 &0.004444\\0.635 & -0.4541 & 525 & 0.001905\\\end{array}

Calculations:

(a) Rise

Δy = y₂ - y₁ = -0.9545 - (-0.4541) = -0.9545 + 0.4541 = -0.5004

(b) Run

Δx = x₂ - x₁ = 0.004 444 - 0.001 905 = 0.002 539 K⁻¹

(c) Slope

Δy/Δx = -0.5004/0.002 539 K⁻¹ = -197.1 K⁻¹

(d) Activation energy

Slope = -Eₐ/R

Eₐ = -R × slope = -8.314 J·K⁻¹mol⁻¹ × (-197.1 K⁻¹) = 1638 J/mol = 1.64 kJ/mol

4 0
3 years ago
LA 7.0 liter balloon at room temperature (22°C) contains hydrogen gas. If the
coldgirl [10]

Answer:

Explanation: Convert temperatures to Kelvins.

22 C = 295 K

30 C = 303 K

According to Charles' law:

V1 / T1 = V2 / T2

7 / 295 = V2 / 303

V2 = (303 * 7) / 295

V2 = 7.18983 Litres which rounds to 7.19 litres.

5 0
2 years ago
Select the correct answer.
Ilia_Sergeevich [38]
Pretty sure it is B.
Because inertia is a tendency to do nothing or remain unchanged.
8 0
2 years ago
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