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4 years ago

6

Calculate the pressure of an enclosed fluid on which a force of 150 N is exerted over an area of 10 cm2. give the answer in pasc

als.

1 answer:

jek_recluse [69]4 years ago

3 0

The pressure of the enclosed fluid is 150000Pa

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Mimi makes a table about the two types of beta decay. A 5 column table with 2 rows. The first column is labeled type of decay wi

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No change in mass number occurs in beta minus decay

Explanation:

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3 years ago

Four identical particles of mass 0.514 kg each are placed at the vertices of a 4.70 m x 4.70 m square and held there by four mas

Alona [7]

In order to solve the problem it is necessary to take into account the concepts related to the moment of inertia, and the center of mass of the object.

Our values are given by:

m = 0.514kg

I = 4.7m (each side)

A) For the case when the axis passes through the midpoints of opposite sidesand lies in the plane of the square. The formula is given by,

$I = 4m (\frac{l}{2})^2\\I = 4*(0.514)(\frac{4.7}{2})^2\\I = 11.35kgm^2\\$

B) For the case when the axis passes through the midpoint of one of the sides and is perpendicular to the plane of the square. The formula is given by,

$I = 2m(\frac{l}{2})^2+2m(\frac{l}{2}^2+l^2)\\I = 2*(0.514)*(\frac{4.7}{2})^2+2*(0.514)*((\frac{4.7}{2})^2+4.7^2)\\I = 34.06Kgm^2$

C) For the case when the axis lies in the plane of square f passes through two diagonally opposite particles,

$I = \frac{1}{2}*l^2$

$I = \frac{1}{2}*(4.7)^2$

$I = 11.045kgm^2$

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3 years ago

The earth has a vertical electric field at the surface, pointing down, that averages 100 N/C. This field is maintained by variou

Kipish [7]

Answer:

The excess charge on earth's surface was calculated to be 4.56 × 10⁵ C

Explanation:

Using the formula for an electric field;

E = kQ/r²

k = 1/(4πε₀) = 8.99 × 10⁹ Nm²/C²

E = 100N/C

r = radius of the earth = 6400 km = 6400000m

Q = Er²/k = 100 × (6400000)²/(8.99 × 10⁹)

Q = 455617.4 C = 4.56 × 10⁵ C

Hope this helps!!!

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4 years ago

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