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Answer:
Kinetic energy of the system = 2547.41 Joules.
Explanation:
Given:
Disk:
Mass of the disk (m) = kg
Radius of the disk (r) = cm =
m
Cylinder:
Mass of the annular cylinder (M) = kg
Inner radius of the cylinder =
m
Outer radius of the cylinder =
m
The angular speed of the system =
rev/s
Angular speed in in terms of Rad/sec = rad/sec
Formula to be used:
Rotational Kinetic energy, =
So, before that we have to work with the moment of inertia (MOI) of the system.
⇒ MOI of the system = MOI of the disk + MOI of the cylinder
⇒ MOI (system) =
⇒ MOI (system) =
⇒ MOI (system) = kg.m^2
Now
The rotational Kinetic energy.
⇒
Plugging the values.
⇒
⇒ Joules
Then
The kinetic energy of the rotational system is 2547.41 J.