A speeding car is travelling at a constant 30.0 m/s when it passes a stationary police car. If the police car delays for 1.00 s
1 answer:
Answer:
option (C)
Explanation:
Speed of car = 30 m/s
Let the time taken by the police car to catch the speeding car is t
The distance traveled by the speeding car in t + 1 second is equal to the distance traveled by the police car in time t
Distance traveled by the police car in time t
.... (1)
Distance traveled by the speeding car in t + 1 second
s = 30 (t + 1) = 300
t + 1 = 10
t = 9 s
Put the value of t in equation (1), we get
300 = 0 + 0.5 x a x 9 x 9
a = 7.41 m/s^2
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Answer:
Hi
Final temperature = 250.11 °C
Final volume = 0,1 m3.
Process work = 0
Explanation:
The specific volume in the initial state is: v = 0.1m3/2 kg = 0.05 m3/kg.
This volume is located between the volumes as saturated liquid and saturated steam at 20 °C. For this reason the water is initially in a liquid vapor mixture. As the piston was blocked the volume remains constant and the process is isometric, also known as isocoric process, so the final temperature will be the water temperature at a saturated steam of v=0.05m3/kg, which is obtained by using steam tables for water, by linear interpolation. As follows, using table A-4 of the Cengel book 7th Edition:
v=0.05 m3/kg
v1=0.057061 m3/kg
T1=242.56°C
v2=0.049779 m3/kg
T2=250.35°C
T=
The process work is zero because there is no change in volume during heating:
W=PxΔv=Px0=0
where
W=process work
P=pressure
Δv=change of volume, is zero because the piston was blocked so the volume remains constant.