3 years ago

4a^2-8a=0solve by competing square

Mathematics

2 answers:

Mandarinka [93]3 years ago

7 0

Answer:

4a²-8a=0

4a(a−2)=0

The final solution is all the values that make 4a(a−2)=0 true.

a=0,2

Step-by-step explanation:

zalisa [80]3 years ago

6 0

Answer:

a=0 or a=2

Hope it helped!

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4a^2-8a=0solve by competing square​

4a^2-8a=0solve by competing square