4/16, 5/20, 6/24, 7/28, 8/32...
The distance traveled in 1 roation is assumed to be the circumferece
c=2pir
in 13 rotations
13 times 2pir=26pir=distance traveled for 13 revolutions
r=13
d=26pi13
d=338pi
using 3.14 for pi
d=1061.32 inches
( x, y ) → ( x-3, y+4 )
A ( 1, 1) → A' (1-3, 1+4) A' (-2, 5)
Answer:
f'(1) = 2
Step-by-step explanation:
f(x) = 2x^2 -2x +3
Take the derivative
f'(x) = 2 * 2x - 2 * 1
f'(x) = 4x -2
f'(1) = 4(1) -2
=4-2
=2
