Question

A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degrees celsius . During the reaction 69.0kJ of heat flows out of the bath and into the flask.Calculate the new temperature of the water bath. You can assume the specific heat capacity of water under these conditions is 4.18J*g*K.

Answer 1

Answer:

309.1K

Explanation:

Step 1: Convert the flown heat to Joule

We will use the relationship 1 kJ = 1,000 J.

$69.0kJ \times \frac{1,000J}{1kJ} = 69.0 \times 10^{3} J$

Step 2: Convert the mass of water to gram

We will use the relationship 1 kg = 1,000 g.

$8.10 kg \times \frac{1,000g}{1kg} = 8.10 \times 10^{3} g$

Step 3: Convert the initial temperature to Kelvin

We will use the following expression.

K = °C + 273.15 = 33.9°C + 273.15 = 307.1 K

Step 4: Calculate the final temperature

We will use the following expression.

$Q = c \times m \times (T_f - T_i)$

where,

• Q: heat

• c: specific heat capacity

• m: mass

• T f: final temperature

• T i: initial temperature

$T_f = \frac{Q}{c \times m} + T_i = \frac{69.0 \times 10^{3}J }{4.18J/g.K \times 8.10 \times 10^{3}g} + 307.1K = 309.1K$