Answer:
B
Explanation:
Oil > Animals > Plants > Chemicals
<h3>
Answer:</h3>
5.00 mol O₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.<u>
</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.01 × 10²⁴ atoms O₂
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:
![\displaystyle 3.01 \cdot 10^{24} \ atoms \ O_2(\frac{1 \ mol \ O_2}{6.022 \cdot 10^{23} \ atoms \ O_2})](https://tex.z-dn.net/?f=%5Cdisplaystyle%203.01%20%5Ccdot%2010%5E%7B24%7D%20%5C%20atoms%20%5C%20O_2%28%5Cfrac%7B1%20%5C%20mol%20%5C%20O_2%7D%7B6.022%20%5Ccdot%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20O_2%7D%29)
- Multiply/Divide:
![\displaystyle 4.99834 \ mol \ O_2](https://tex.z-dn.net/?f=%5Cdisplaystyle%204.99834%20%5C%20mol%20%5C%20O_2)
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
4.99834 mol O₂ ≈ 5.00 mol O₂
Answer:
648.5 mL
Explanation:
Here we will assume that the pressure of the gas is constant, since it is not given or specified.
Therefore, we can use Charle's law, which states that:
"For an ideal gas kept at constant pressure, the volume of the gas is proportional to its absolute temperature"
Mathematically:
![\frac{V}{T}=const.](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7BT%7D%3Dconst.)
where
V is the volume of the gas
T is its absolute temperature
The equation can be rewritten as
![\frac{V_1}{T_1}=\frac{V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BV_1%7D%7BT_1%7D%3D%5Cfrac%7BV_2%7D%7BT_2%7D)
where in this problem we have:
is the initial volume of the gas
is the initial temperature
is the final temperature
Solving for V2, we find the final volume of the gas:
![V_2=\frac{V_1 T_2}{T_1}=\frac{(490)(315)}{238}=648.5 mL](https://tex.z-dn.net/?f=V_2%3D%5Cfrac%7BV_1%20T_2%7D%7BT_1%7D%3D%5Cfrac%7B%28490%29%28315%29%7D%7B238%7D%3D648.5%20mL)