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guajiro [1.7K]
3 years ago
11

What mass of copper is required to replace silver from 4.00g of silver nitrate dissolved in water?

Chemistry
1 answer:
larisa [96]3 years ago
3 0
The balanced chemical reaction is written as:

<span>Cu +2AgNO3 → Cu(NO3)2 + 2Ag
</span>
We are given the amount of silver nitrate to be used for the reaction. This value will be the starting point of our calculations. It is as follows:

4.00 g AgNO3 ( 1 mol / 169.87 g ) ( 1 mol Cu / 2 mol AgNO3 ) ( 63.456 g / 1 mol ) = 0.747 g Cu
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An ion with 11 protons 12 neutrons and a charge of + 1 has an atomic number of
posledela

Answer:

11 electrons total and 23amu

Explanation:

This tells us that sodium has 11 protons and because it is neutral it has 11 electrons. The mass number of an element tells us the number of protons AND neutrons in an atom (the two particles that have a measurable mass). Sodium has a mass number of 23amu.

5 0
3 years ago
A reasonable pka for a weak base is:<br><br> 10.3<br><br> 0.9<br><br> 5.8<br><br> 7.4<br><br> 13.1
andriy [413]

Answer:

0.9

Explanation:

The pka represents the force by which the molecules need to dissociate for the acids ,

Hence , lower the pka stronger will be the acid and that therefore will  dissociate completely and vice versa , for a weak acid higher the pka .

And in case of a base , it will be completely reversed , lower pKa , weaker base ,

and higher pKa , stronger base .

From the data of the question ,

0.9 is the lowest value of the pKa , hence , weakest base .

7 0
3 years ago
Let's say you have a mixture for which you want to check the composition. Unfortunately, after quite a while, and several TLC an
KIM [24]

Answer:

mmmmmmmmmmmmmm

Explanation:

7 0
3 years ago
When an electron is displaced in a semiconductor, the hole that's left behind is
geniusboy [140]
<span>answer is A : attracted to the negative terminal of the voltage source
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5 0
3 years ago
Read 2 more answers
Calculate the ph of a 0.20 m solution of iodic acid (hio3, ka = 0.17).
saveliy_v [14]
Iodic acid partially dissociates into H+ and IO3- 
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Ka = [H+] [IO3-] / [HIO3]; 
<span>Initially, [H+] ≈ [IO3-] = 0 and [HIO3] = 0.20; </span>
<span>At equilibrium [H+] ≈ [IO3-] = x and [HIO3] = 0.20 - x; </span>
<span>so 0.17 = x² / (0.20 - x); </span>
<span>Solving for x using the quadratic formula: </span>
<span>x = [H+] = 0.063 M or pH = - log [H+] = 1.2.</span>
7 0
4 years ago
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