Question

If excess sodium is added to 0.10 L of 1.00 M hydrochloric acid solution, how many moles of NaCl is formed?

Answer 1

Answer:

=> 0.10 moles

Explanation:

The question is asking us to find the moles of NaCl cid formed.

We have been provided with;

0.10 L of 1.0 M NaOH.

We know that mole ratio of the reaction is 1:1 and also the molarity of a solution is contained in 1 L or 1000 mL or 1000 cm³.

This means that;

1.0 M is contained in 1.0 L.

X mol is contained in 0.10 L

$x \: mol \: = \frac{0.1 \times 1.0}{1.0} \\ = 0.10 \: mol$

= 0.10 moles of NaCl formed