If excess sodium is added to 0.10 L of 1.00 M hydrochloric acid solution, how many moles of NaCl is formed?
1 answer:
Answer:
=> 0.10 moles
Explanation:
The question is asking us to find the moles of NaCl cid formed.
We have been provided with;
0.10 L of 1.0 M NaOH.
We know that mole ratio of the reaction is 1:1 and also the molarity of a solution is contained in 1 L or 1000 mL or 1000 cm³.
This means that;
1.0 M is contained in 1.0 L.
X mol is contained in 0.10 L
= 0.10 moles of NaCl formed
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The compound sodium carbonate is a strong electrolyte because it completely dissociates when placed in water into its component ions. The equation of the reaction can be expressed as:
The dissociation leads to the formation of sodium and carbonate ions with the latter held together by its internal covalent bond.
This is unlike weak electrolytes that do not dissociate completely in water or aqueous solutions. Only a small fraction of the solute exists as ions in the solution.
More on strong and weak electrolytes can be found here: brainly.com/question/3410548