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Sergio039 [100]
3 years ago
10

The compound sodium carbonate is a strong electrolyte. Write the reaction when solid sodium carbonate is put into water:

Chemistry
1 answer:
Ludmilka [50]3 years ago
7 0

The compound sodium carbonate is a strong electrolyte because it completely dissociates when placed in water into its component ions. The equation of the reaction can be expressed as:

Na_2CO_3_{(s)} ---> 2 Na^+_{(aq)} + CO_3^{(2+)}_{(aq)}

The dissociation leads to the formation of sodium and carbonate ions with the latter held together by its internal covalent bond.

This is unlike weak electrolytes that do not dissociate completely in water or aqueous solutions. Only a small fraction of the solute exists as ions in the solution.

More on strong and weak electrolytes can be found here: brainly.com/question/3410548

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What mass of CO2 can be produced from the decomposition of 4.8 moles of Fe2(CO3)3?
gavmur [86]

Answer: 633.6 g of CO_2 can be produced from the decomposition of 4.8 moles of Fe_2(CO_3)_3

Explanation:

The balanced chemical equation for decomposition of Fe_2(CO_3)_2 is :

Fe_2(CO_3)_2\rightarrow Fe_2O_3+3CO_2

According to stoichiometry :

1 mole of Fe_2(CO_3)_2 produce = 3 moles of CO_2

Thus 4.8 moles of Fe_2(CO_3)_2 will rproduce=\frac{3}{1}\times 4.8=14.4moles  of CO_2

Mass of CO_2=moles\times {\text {Molar mass}}=14.4moles\times 44g/mol=633.6g

Thus 633.6 g of CO_2 can be produced from the decomposition of 4.8 moles of Fe_2(CO_3)_3

7 0
3 years ago
Based of the chemical reaction below, if you have 3.56x10^23 molecules of C3H8, how many liters of CO2 gas will be produced at S
LenaWriter [7]

Answer:

39.65L

Explanation:

First, let us calculate the number of mole present in 3.56x10^23 molecules of C3H8.

1 mole of any substance contains 6.02x10^23 molecules as discovered from Avogadro's hypothesis. This means that 1mole of C3H8 contains 6.02x10^23 molecules.

Now, if 1mole of C3H8 contains 6.02x10^23 molecules, then Xmol of C3H8 will contain 3.56x10^23 molecules i.e

Xmol of C3H8 = 3.56x10^23/6.02x10^23 = 0.59mole

The equation for the reaction is given below:

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From the equation above,

1 mole of C3H8 produced 3moles of CO2.

Therefore, 0.59mole of C3H8 will produce = 0.59 x 3 = 1.77mole of CO2.

Now let us calculate the volume occupied by 1.77mole of CO2. This is illustrated below:

1 mole of any gas occupy 22.4L at stp.

Therefore, 1.77mole of CO2 will occupy = 1.77 x 22.4 = 39.65L

Therefore, 39.65L of CO2 are produced.

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