All categories

1 year ago

In which of the following intervals does the trigonometric inequality sec(x) < cot(x) always hold true.

Mathematics

1 answer:

Ray Of Light [21]1 year ago

8 0

The inequality for sec (x) < cot (x) is; π/2 < x < π

<h3>How to express trigonometric inequality?</h3>

We are given that;

We want to find the intervals that the trigonometric inequality sec (x) < cot (x) always hold true.

This can also be expressed as;

1/cos (x) < 1/tan (x)

Now, this can happen only in the quadrant where tan (x) is negative and cos x is positive which is in fourth quadrant where;

π/2 < x < π

The inequality for sec (x) < cot (x) is; π/2 < x < π

Read more about Trigonometric Inequality at; brainly.com/question/12094532

#SPJ1

You might be interested in

Someoneee helppp meee plzzzz

shepuryov [24]

Sorry I’m wrong I took geometry like 3 years ago so I might forget some

11. SSS
12. AAS
13 Not possible
14. ASA
15. SAS
16.ASA

8 0

3 years ago

Can someone help me on 6?

fomenos

Answer:

66600 ft

Step-by-step explanation:

First draw a rectangle and draw a diagonal line in the middle. The line makes two triangles, and the line itself is the hypotenuse. So, to find hypotenuse, the formula is:

a^2 + b^2 = c^2

The variable c defines the hypotenuse. Therefore:

a = 150

b = 210

Let's solve:

150^2 + 210^2 = c^2

22500 + 44100 = c^2

66600 = c^2

Therefore, in conclusion, the result we are getting is 66600 ft.

<u><em>Hope This Helps!</em></u>

6 0

2 years ago

Read 2 more answers

A sofa regularly sells for 860. The sale price is 670.80. Find the percent decrease of the sale price from the regular price

andre [41]

Answer:

-22%

Step-by-step explanation:

The percent decrease can be found by subtracting the original amount from the sale price. Divide the result by the original price and multiplying the decimal by 100 for the percent.

670.80 - 860 = -189.2

-189.2/860 = -0.22

-0.22*100 = -22%

4 0

3 years ago

Use this graph of velocity vs. time for two objects to answer the question.

Lynna [10]

Using derivatives, it is found that the correct option is:

A. Object C has an acceleration that is greater than the acceleration for D.

The acceleration is the <u>derivative of the velocity</u>, given by change in velocity divided by change in time, that is:

$a = \frac{\Delta_v}{\Delta_t}$

In this problem:

The change in time for objects C and T is the same.
The <u>change in velocity for object C is greater</u>, thus, it has a greater acceleration, and the correct option is:

A. Object C has an acceleration that is greater than the acceleration for D.

A similar problem is given at brainly.com/question/14516604

6 0

2 years ago

Read 2 more answers

. For the function given, state the starting point for a sample period:

Aneli [31]

I think the answer is π?

8 0

3 years ago