The inequality for sec (x) < cot (x) is; π/2 < x < π
We are given that;
We want to find the intervals that the trigonometric inequality sec (x) < cot (x) always hold true.
This can also be expressed as;
1/cos (x) < 1/tan (x)
Now, this can happen only in the quadrant where tan (x) is negative and cos x is positive which is in fourth quadrant where;
π/2 < x < π
Read more about Trigonometric Inequality at; brainly.com/question/12094532
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Answer:
Step-by-step explanation:
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I think the answers are A and C. Hope this helps ☺
f(x) = −2(0.7)x
That is the answer because we have to change a percent to a decimal and that is the only option.
