Question

In which of the following intervals does the trigonometric inequality sec(x) < cot(x) always hold true.

Answer 1

The inequality for sec (x) < cot (x) is;  π/2 < x < π

How to express trigonometric inequality?

We are given that;

We want to find the intervals that the trigonometric inequality sec (x) < cot (x) always hold true.

This can also be expressed as;

1/cos (x) < 1/tan (x)

Now, this can happen only in the quadrant where tan (x) is negative and cos x is positive which is in fourth quadrant where;

π/2 < x < π

The inequality for sec (x) < cot (x) is;  π/2 < x < π

Read more about Trigonometric Inequality at; brainly.com/question/12094532

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