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lys-0071 [83]
2 years ago
6

The following graph describes function 1, and the equation below it describes function 2. Determine which function has a greater

maximum value, and provide the ordered pair. (1 point)
Function 1

graph of function f of x equals negative x squared plus 8 multiplied by x minus 15

Function 2

f(x) = −x2 + 2x − 3

Function 1 has the larger maximum at (1, 4).

Function 1 has the larger maximum at (4, 1).

Function 2 has the larger maximum at (1, −2).

Function 2 has the larger maximum at (−2, 1).
13.

Mathematics
1 answer:
sineoko [7]2 years ago
3 0

Answer: Function 1 has the larger maximum at (4,1).

Step-by-step explanation:

The vertex of f(x) is at x=-\frac{2}{2(-1)}=1, and f(1)=-2.

For the graph, the maximum is obviously at (4,1).

So, Function 1 has the larger maximum at (4,1).

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Suppose the diameter of a circle is 10. What is its area?
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Parallelogram MNPQ was dilated to create parallelogram M'N'P'Q'. On a coordinate plane, 2 parallelograms are shown. Parallelogra
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Answer:

The answer is below

Step-by-step explanation:

Which statements are true about the parallelograms? Check all that apply.

The length of side MN is 2 units.

The length of side M'N' is 5 units.

The image is smaller than the pre-image.

Sides MQ and M'Q' both have the same slope, 1.

The scale factor is 2/5

a) The length of side MN is determined using the formula:

|MN|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(4-2)^2+(-2-(-2))^2}=\sqrt{2^2}=2\\  \\ |MN|=2

The first option is correct

b) The length of side M'N' is determined using the formula:

|M'N'|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(10-5)^2+(-5-(-5))^2}=\sqrt{5^2}=2\\  \\ |M'N'|=5

The second option is correct

c) From the coordinates of parallelogram MNPQ and M'N'P'Q', we can see that parallelogram MNPQ is dilated by a factor of 5/2 to produce parallelogram M'N'P'Q' , hence parallelogram M'N'P'Q'  is bigger that parallelogram MNPQ. This means that The image is bigger than the pre-image.

The third option is wrong

d) The slopes are given as:

Slope\ of\ MQ=\frac{Change\ in\ y}{Change\ in\ x}=\frac{1-2}{-3-(-2)} =1\\ \\Slope\ of\ M'Q'=\frac{Change\ in\ y}{Change\ in\ x}=\frac{3-5}{-7-(-5)} =1\\

Option four is correct

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Option 5 is wrong

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