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mamaluj [8]
1 year ago
8

Which of the following is the graph of y = -2√x-3+2?

Mathematics
1 answer:
snow_lady [41]1 year ago
8 0

I presume you meant y=-2\sqrt{x-3}+2.

The graph is shown in the attached image.

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145%
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It looks like the differential equation is

\dfrac{dy}{dx} = \dfrac{xy + 3x - y - 3}{xy - 2x + 4y - 8}

Factorize the right side by grouping.

xy + 3x - y - 3 = x (y + 3) - (y + 3) = (x - 1) (y + 3)

xy - 2x + 4y - 8 = x (y - 2) + 4 (y - 2) = (x + 4) (y - 2)

Now we can separate variables as

\dfrac{dy}{dx} = \dfrac{(x-1)(y+3)}{(x+4)(y-2)} \implies \dfrac{y-2}{y+3} \, dy = \dfrac{x-1}{x+4} \, dx

Integrate both sides.

\displaystyle \int \frac{y-2}{y+3} \, dy = \int \frac{x-1}{x+4} \, dx

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\implies \boxed{y - 5 \ln|y + 3| = x - 5 \ln|x + 4| + C}

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1 year ago
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Answer:

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Step-by-step explanation:

So we have the system of equations:

5x-2y=16\\15x-7y=51

And we want to multiply the first equation by some constant such that the resulting equation matches the coefficient of [x] in the second equation.

We can see that the coefficient of x in the second equation is 15.

So, to match 15, we must multiply the first equation by 3. So:

3(5x-2y)=3(16)

Multiply:

15x-6y=48

And we're done!

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Step-by-step explanation:

Yr old address and I will run through it ASAP 68o9

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Answer:

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