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erma4kov [3.2K]
3 years ago
5

How many chiral centers does clavulanic acid have?

Chemistry
1 answer:
VikaD [51]3 years ago
7 0

Answer:

Clavulanic acid has two (2) chiral centers.

Explanation:

A chiral center is a center (usually carbon) with four different substituents.

The structure of clavulanic acid is shown in the attachment below.

Consider the labeled diagram in the attachment,

Carbon A is not a chiral carbon because it has two hydrogen atoms attached to it

Carbon B is not a chiral carbon because it has only three substituents

Carbon C is a chiral carbon because it has four different substituents

Carbon D is a chiral carbon because it has four different substituents

Carbon E is not a chiral carbon because it has only three atoms directly attached to it

Carbon F is not a chiral carbon because it has only three atoms directly attached to it

Carbon G is not a chiral carbon because it has two hydrogen atoms attached to it

Carbon H is not a chiral carbon because it has only three substituents

Then, only carbons C and D are chiral carbons.

Hence, clavulanic acid have two (2) chiral centers.

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the heat of fusion of acetone is 5.7 kJ/mol. Calculate to two significant figures the entropy change when 6.3 mol of acetone mel
shtirl [24]

<u>Answer:</u> The entropy change of the process is 2.0\times 10^2J/K

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To calculate the entropy change for different phase at same temperature, we use the equation:

\Delta S=n\times \frac{\Delta H_{f}}{T}

where,  

\Delta S = Entropy change

n = moles of acetone = 6.3 moles

\Delta H_{f} = enthalpy of fusion = 5.7 kJ/mol = 5700 J/mol    (Conversion factor:  1 kJ = 1000 J)

T = temperature of the system = -94.7^oC=[273-94.7]=178.3K

Putting values in above equation, we get:

\Delta S=\frac{6.3mol\times 5700J/mol}{178.3K}\\\\\Delta S=201.4J/K=2.0\times 10^2J/K

Hence, the entropy change of the process is 2.0\times 10^2J/K

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