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irina [24]
3 years ago
7

Why is the atomic mass of most elements not a whole number?

Chemistry
1 answer:
Crank3 years ago
3 0
The atomic mass is the average of the isotopes of the element meaning most averages of isotopes will not be whole numbers
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What is the full number for 5.7x10^4
dsp73

Answer:

5.7*10^4 is equal to 57,000.

Explanation:

First, we must multiply 10 by its power, 4. That would be 10 4 times.

10*10*10*10 = 10,000.

Then, we multiply it by 5.7.

5.7*10,000 = 57,000.

Regards!

3 0
3 years ago
Is hydrogen monoxide covalent or ionic
Anika [276]

Answer:

ionic

Explanation:

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3 0
3 years ago
How many seconds does it take a race horse to run six furlongs at 40.7 miles per hour if: I furlong = 40 rods; 5.5 yards = 1 rod
lana [24]

Distance traveled by the race horse=6 furlongs

Converting the distance from furlongs to rods: 40 rods =1 furlong

6 furlongs*\frac{40rods}{1furlong} =240rods

Converting the distance from rods to yards, feet and miles: 5.5 yards = 1 rod, 3foot =1 yard, 1 mile = 5280 feet.

240rods*\frac{5.5yards}{1rod}*\frac{3foot}{1yard}*\frac{1mi}{5280feet}=0.75mi

The given speed of race horse = 40.7mi/hr

Calculating the time required:

0.75mi*\frac{1hr}{40.7mi}*\frac{60min}{1hr}*\frac{60s}{1min}= 66.34s

Therefore, 66.34 s is required for a race horse to run six furlongs at 40.7 miles per hour.

8 0
3 years ago
A chemical substance that increases the reaction rate and lowers the activation energy needed to start a reaction is
Elza [17]
A catalyst lowers the activation energy needed to start a reaction
4 0
3 years ago
Read 2 more answers
Calculate the volume in L of 11.6 moles of Neon at 120 K when it has a pressure of 25.9 atm
beks73 [17]

Answer:

The volume of the gas is approximately 4.41 liters

Explanation:

The details of the data of the Neon gas are;

The number of moles of Neon gas present, n = 11.6 moles

The temperature of the sample of Neon gas, T = 120 K

The pressure of the sample of the Neon gas, P = 25.6 atm

By the ideal gas equation, we have;

P·V = n·R·T

Where;

R = The universal gal constant = 0.08205 L·atm·mol⁻¹·K⁻¹

Therefore, we get;

V = n·R·T/P

Which gives;

V = 11.6 moles × 0.08205 L·atm·mol⁻¹·K⁻¹ × 120 K/(25.9 atm) ≈ 4.4097915 L

The volume of the gas, V ≈ 4.41 L.

7 0
3 years ago
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