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jeka94
3 years ago
5

A type of emergency apparatus that can be used where oxygen may be limited or where the air might be poisoned is based on the fo

llowing reaction in which CO2 produced by your own respiration reacts and O2 gas is produced. Calculate the mass of KO2 needed to produce 25 g of oxygen gas.
4 KO2(s) + 2 CO2(g)  2 K2CO3(s) + 3 O2 (g)
Chemistry
1 answer:
Bess [88]3 years ago
8 0

Answer:

so I don't know how to answer that

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Aluminum sulfate, known as cake alum, has a wide range of uses, from dyeing leather and cloth to purifying sewage. In aqueous so
NISA [10]

Answer:

a) The chemical reaction is given as:

6NaOH(aq)+Al_2(SO_4)_3\rightarrow 2Al(OH)_3(s)+3Na_2SO_4(aq)

2.571 grams of aluminum hydroxide is precipitated.

Explanation:

a) The chemical reaction is given as:

6NaOH(aq)+Al_2(SO_4)_3\rightarrow 2Al(OH)_3(s)+3Na_2SO_4(aq)

b)

Moles of NaOH = n

Volume of the NaOH = 185.5 mL = 0.1855 L( 1 mL =0.001 L)

Molarity of the solution = 0.533 M

n=0.533 M\times 0.1855 mL=0.09887 mol

Moles of aluminum = n

15.8 g of aluminum sulfate per liter.

Volume of solution = 627 mL = 0.627 L (1 mL= 0.001 L)

Mass of aluminium sulfate in solution = 15.8 g/L × 0.627 L =9.9066 g

Moles of aluminum sulfate = \frac{9.9066 g}{342 g/mol}=0.02897 mol

Moles of NaOH = 0.09887 mol

According to reaction, 6 moles of NaOH reacts with 1 mole of aluminum sulfate, then 0.09887 moles of NaOH will recat with :

\frac{1}{6}\times 0.09887 mol=0.01648 mol

This means that sodium hydroxide moles are in limiting amount.So, amount of aluminum hydroxide will depend upon moles of sodium hydroxide.

According to reaction, 6 moles of sodium hydroxide gives 2 moles of aluminium hydroxide, then 0.09887 moles of sodium hydroxide will give :

\frac{2}{6}\times 0.09887 mol=0.03296 mol of aluminum hydroxide

Mass of 0.03296 moles of aluminum hydroxide:

0.03296 mol × 78 g/mol = 2.571 g

2.571 grams of aluminum hydroxide is precipitated.

8 0
3 years ago
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