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jeka94
3 years ago
5

A type of emergency apparatus that can be used where oxygen may be limited or where the air might be poisoned is based on the fo

llowing reaction in which CO2 produced by your own respiration reacts and O2 gas is produced. Calculate the mass of KO2 needed to produce 25 g of oxygen gas.
4 KO2(s) + 2 CO2(g)  2 K2CO3(s) + 3 O2 (g)
Chemistry
1 answer:
Bess [88]3 years ago
8 0

Answer:

so I don't know how to answer that

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The elementary reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) 2H2O(g)↽−−⇀2H2(g)+O2(g) proceeds at a certain temperature until the partial pres
Dima020 [189]

Answer:

6.25\times 10^{-6} is the value of the equilibrium constant at this temperature.

Explanation:

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of products to the partial pressures  of reactants each raised to the power equal to their stoichiometric ratios. It is expressed as K_{p}

2H_2O(g)\rightleftharpoons 2H_2(g)+O_2(g)

Partial pressures at equilibrium:

p^o_{H_2O}=0.070 atm

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The equilibrium constant in terms of pressures is given as:

K_p=\frac{(p^o_{H_2})^2\times (p^o_{O_2})}{(p^o_{H_2O})62}

K_p=\frac{(0.0035 atm)^2\times 0.0025 atm}{(0.070 atm)^2}=6.25\times 10^{-6}

6.25\times 10^{-6} is the value of the equilibrium constant at this temperature.

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