2 years ago

Factor: 128 + 2d^3 cubes lol

Mathematics

1 answer:

BARSIC [14]2 years ago

4 0

The factorization if the given expression 128 + 2d³ is 2(64 + d³).

<h3>Factorization</h3>

128 + 2d³

There are two parameters in the expression;

128
2d³

The common factors between 128 and 2d³ is 2

So,

128 + 2d³

= 2(64 + d³)

Learn more about factorization:

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Gemiola [76]

One possible way:
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grin007 [14]

Answer:

Step-by-step explanation:

First, turn the word problem into an equation:

n(a number) was divided by 2

$\frac{n}{2}$

followed by this quotient beying multiplied by 4

$\frac{n}{2}$ *4

the product was added to 9

$\frac{n}{2}$ *4+9

the total sum was 25

$\frac{n}{2}$ *4+9 = 25

use PEMDAS to solve the equation

subtract 9 on both sides

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zaharov [31]

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Step-by-step explanation:

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