Answer: 1 is not a perfect square. 3 is the only prime number one less than a square.
Answer:
(7 x + 6 y)^2
Step-by-step explanation:
Factor the following:
49 x^2 + 84 x y + 36 y^2
The coefficient of x^2 is 49 and the coefficient of y^2 is 36. The product of 49 and 36 is 1764. The factors of 1764 which sum to 84 are 42 and 42. So 49 x^2 + 84 x y + 36 y^2 = 49 x^2 + 42 x y + 42 x y + 36 y^2 = 7 x (7 x + 6 y) + 6 y (7 x + 6 y):
7 x (7 x + 6 y) + 6 y (7 x + 6 y)
Factor 7 x + 6 y from 7 x (7 x + 6 y) + 6 y (7 x + 6 y):
(7 x + 6 y) (7 x + 6 y)
(7 x + 6 y) (7 x + 6 y) = (7 x + 6 y)^2:
Answer: (7 x + 6 y)^2
Answer:
Three circular arcs of radius $5$ units bound the region shown. Arcs $AB$ and $AD$ are quarter-circles, and arc $BCD$ is a semicircle.
Step-by-step explanation:
Answer: (6a + 5b) • (6a - 5b)
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "b2" was replaced by "b^2". 1 more similar replacement(s).
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(36 • (a2)) - 52b2
Step 2 :
Equation at the end of step 2 :
(22•32a2) - 52b2
Step 3 :
Trying to factor as a Difference of Squares :
3.1 Factoring: 36a2-25b2
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 36 is the square of 6
Check : 25 is the square of 5
Check : a2 is the square of a1
Check : b2 is the square of b1
Factorization is : (6a + 5b) • (6a - 5b)
Final result :
(6a + 5b) • (6a - 5b)
brainly would epic!
Answer:
13 unit
Step-by-step explanation:
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