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Thepotemich [5.8K]
2 years ago
10

Using desmos

Mathematics
1 answer:
VMariaS [17]2 years ago
8 0

The attached graph represents the location of the pH values 0 and 1

<h3>How to plot the points?</h3>

The given parameters are:

pH value 0 = (1, 0)

pH value 1 = (0.1, 1)

This means that we plot a point at the coordinate (1, 0) and another point at the coordinate (0.1, 1).

See attachment for the graph

Read more about graphs at:

brainly.com/question/4025726

#SPJ1

<u>Complete question</u>

The pH value is 0 at (1, 0) and 1 at (0.1, 1).

Using desmos

A. Locate, plot, and label on your graph where the pH value is 0.1

B. Locate, plot, and label on your graph where the pH value is 1.

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Find the value of x<br> What’s the missing angle?
cupoosta [38]

Answer:

x = 15, 72 degrees

Step-by-step explanation:

4x + 12 + 108 = 180

4x + 120 = 180

4x (+ 120 - 120) = 180 - 120

4x = 60

4x/4 = 60/4

x = 15

4x + 12

4(15) + 12

60 + 12

72 degrees

3 0
2 years ago
Please help posted picture of question
Leni [432]
Hello!

First you factor 28

2^2 * 7 = 28

Now we have

\sqrt{2^{2} }  \sqrt{7}

If you take a square root of a square number they cancel out

2 \sqrt{7}

The answer is B)2 \sqrt{7}

Hope this helps!
8 0
3 years ago
Suppose a random sample of 25 students is selected from a community college where the scores in the final exam (out of 125 point
BartSMP [9]

Answer:

he probability that the sample mean deviates from the population mean = 112 by no more than 4= 0.9050

Step-by-step explanation:

mean = 112

sd = 12/sqrt(25) = 2.4

z = (x - μ)/σ

z = (116 - 112)/2.4 = 1.67

Therefore,

P(X >= 116) = P(z <= (116 - 112)/2.4)

= P(z >= 1.67)

= 1 - 0.9525

= 0.0475

z = (x - μ)/σ

z1 = (108 - 112)/2.4 = -1.67

z2 = (116 - 112)/2.4 = 1.67

Therefore, we get

P(108 <= X <= 116) = P((116 - 112)/2.4) <= z <= (116 - 112)/2.4)

= P(-1.67 <= z <= 1.67) = P(z <= 1.67) - P(z <= -1.67)

= 0.9525 - 0.0475

= 0.9050

6 0
3 years ago
Tell me quick and i will give thou brainliest
Anit [1.1K]

c, the answer is going by 3, so it is c.


7 0
3 years ago
Read 2 more answers
PLEASE HELP
valina [46]

Answer:

Step-by-step explanation:

You have 3 unknowns: a, b, and c.  It's our job to find them algebraically.  I'm going to start with the point where x = 0 and y = 7.  You'll see why in a minute.  Filling in the standard form of a quadratic

y=ax^2+bx+c  using (0, 7):

7=a(0)^2+b(0)+c  gives you that c = 7.  We will use that value now when we write the next 2 equations.  Now the point (-2, 19):

19=a(-2)^2+b(-2)+7  and

19=4a-2b+7 so

12 = 4a - 2b

Now for the next point (-1, 12):

12=a(-1)^2+b(-1)+7  and

12=a-b+7  so

5 = a - b

Now we have a system of equations (the 2 bold font equations) that we will solve by elimination:

 12  =  4a  -  2b

  5  =   a   -    b

Multiply the bottom equation by -4 to get a new system:

 12  =  4a  -  2b

-20  = -4a  +  4b

Add those together to get rid of the a terms and end up with

-8 = 2b so

b = -4

Now we can sub in -4 for b to solve for a.  I'm using the second bold type equation to do this:

5 = a - (-4) and

5 = a + 4 so

a = 1 and the equation for the quadratic function is

y=x^2-4x+7

7 0
3 years ago
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