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1 year ago

Using desmos

Mathematics

1 answer:

VMariaS [17]1 year ago

8 0

The attached graph represents the location of the pH values 0 and 1

<h3>How to plot the points?</h3>

The given parameters are:

pH value 0 = (1, 0)

pH value 1 = (0.1, 1)

This means that we plot a point at the coordinate (1, 0) and another point at the coordinate (0.1, 1).

See attachment for the graph

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(4, -2), y = –2x + 3<br><br> PLS HELP HOW DO I DO THIS?

Alex787 [66]

It looks like your instructor wants you to write in point-slope form.

the equation for point slope form is quite simple

y-y1=m(x-x1)

your variables:

y and x: just state these as they are

m: slope

y1 and x1: the numbers in the point given

keep in mind a double negative equals a positive, so when you come across a negative coordinate you would put + instead of - in your equation.

your final answer would be

y+2=-2(x-4)

I hope this helped :)

please don't hesitate to ask if you have any more questions

3 0

1 year ago

Conplete the square to solve the quadratic equation. x<br><img src="https://tex.z-dn.net/?f=1%20%7Bx%7D%5E%7B2%7D%20%20-%206x%20

o-na [289]

Answer:

$\large\boxed{x=4\pm2\sqrt6}$

Step-by-step explanation:

$x^2-6x+12=2x+20\qquad\text{subtract}\ 2x\ \text{and}\ 12\ \text{from both sides}\\\\x^2-8x=8\\\\x^2-2(x)(4)=8\qquad\text{add}\ 4^2=16\ \text{to both sides}\\\\x^2-2(x)(4)+4^2=8+4^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(x-4)^2=24\iff x-4=\pm\sqrt{24}\\\\x-4=\pm\sqrt{4\cdot6}\\\\x-4=\pm\sqrt4\cdot\sqrt6\\\\x-4=\pm2\sqrt6\qquad\text{add 4 to both sides}\\\\x=4\pm2\sqrt6$

6 0

2 years ago

Help fast don’t understand

Pani-rosa [81]

200!!!! because it’s 5x20 in each triangle and you divide by 2 so 5x20 is 100 and 100 divided by 2 is 50 and there are 4 squares so 50 x 4 and you get 200 hope that helped!!

7 0

2 years ago

Read 2 more answers

SOMEONE HELP ME ASAP PLZZ!!!

Black_prince [1.1K]

Answer:

The distance of the plane from the base of the tower is 25.5 foot.

Step-by-step explanation:

As given

Max is in a control tower at a small airport.

He is located 50 feet above the ground when he spots a small plane on the runway at an angle of depression of 27°.

Now by using the trigonometric identity.