Using desmos
1 answer:
The attached graph represents the location of the pH values 0 and 1
<h3>How to plot the points?</h3>The given parameters are:
pH value 0 = (1, 0)
pH value 1 = (0.1, 1)
This means that we plot a point at the coordinate (1, 0) and another point at the coordinate (0.1, 1).
See attachment for the graph
Read more about graphs at:
#SPJ1
<u>Complete question</u>
The pH value is 0 at (1, 0) and 1 at (0.1, 1).
Using desmos
A. Locate, plot, and label on your graph where the pH value is 0.1
B. Locate, plot, and label on your graph where the pH value is 1.
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- Let's find slope first.
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- (-8,6)
Slope intercept form
The picture in the attached figure
Part 1) <span>What is the total area of the swimming pool?
</span>
we know that
<span>area of the swimming pool=area rectangle-area semi circle
area rectangle=20*36-----> 720 ft</span>²
area semicircle=pi*r²/2
r=18/2----> 9 ft
area semicircle=pi*9²/2----> 127.17 ft²
area of the swimming pool=720 ft²-127.17 ft²----> 592.83 ft²
the answer Part 1) is
The area of the swimming pool is 592.83 ft²
Part 2) <span>What is the perimeter of the swimming pool?
</span>
perimeter of the swimming pool=perimeter of rectangle-18 ft+perimeter semi circle
perimeter of rectangle=2*[20+36]---> 112 ft
perimeter semi circle=2*pi*r/2----> pi*r
r=9 ft
perimeter semi circle=pi*9----> 28.26 ft
so
perimeter of the swimming pool=112 ft-18 ft+28.26 ft----> 122.26 ft
the answer Part 2) is
122.26 ft
Part 1) <span>What is the total area of the swimming pool?
</span>
we know that
<span>area of the swimming pool=area rectangle-area semi circle
area rectangle=20*36-----> 720 ft</span>²
area semicircle=pi*r²/2
r=18/2----> 9 ft
area semicircle=pi*9²/2----> 127.17 ft²
area of the swimming pool=720 ft²-127.17 ft²----> 592.83 ft²
the answer Part 1) is
The area of the swimming pool is 592.83 ft²
Part 2) <span>What is the perimeter of the swimming pool?
</span>
perimeter of the swimming pool=perimeter of rectangle-18 ft+perimeter semi circle
perimeter of rectangle=2*[20+36]---> 112 ft
perimeter semi circle=2*pi*r/2----> pi*r
r=9 ft
perimeter semi circle=pi*9----> 28.26 ft
so
perimeter of the swimming pool=112 ft-18 ft+28.26 ft----> 122.26 ft
the answer Part 2) is
122.26 ft