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Ivahew [28]
3 years ago
14

Which is equivalent to Cubic root of x^10 after it has been simplified completely?

Mathematics
1 answer:
Maslowich3 years ago
4 0
When we say cubic root, it means that the exponent of your divisor is three. You can solve this by counting how many three's are there in a ten. So there are three three's. the other x has an exponent one and therefore is denoted by ∛x. The answer would be x³∛x.
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What is 4/6 ÷8/14???????????????
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GIVING 20 POINTS AND A BRAINLIEST!!!! (Really need help please!)
Murljashka [212]

Answer:

Step-by-step explanation:

General form of quadratic equation:

ax^2+bx+c=0

ax^2+bx=-c

To complete the square, we will divide the coefficient of x in the general quadratic equation as written above and divide by 2

I'm the question;

x^2-20x+13=0

x^2-20x=-13

The coefficient of x =-20

Divide the coefficient by 2 and square the result afterwards

-20/2= - 10

(-10)^2= 100

Add 100 to both sides of the equation

x^2-20x+100=-13+100

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The failure of a circuit board interrupts work that utilizes a computing system until a new board is delivered. The delivery tim
Hatshy [7]

Answer:

The expected cost is 152

Step-by-step explanation:

Recall that since Y is uniformly distributed over the interval [1,5] we have the following probability density function for Y

f_Y(y ) = \frac{1}{5-1} = \frac{1}{4} if 1\leq y \leq 5 and 0 othewise. (To check this is the pdf, check the definition of an uniform random variable)

Recall that, by definition  

E(Y^k) = \int_{-\infty}^{\infty} y^kf_Y(y)dy

Also, we are given that C = 50+3Y+9Y^2. Recall the following properties of the expected value. If X,Y are random variables, then

E(a+bX+cY) = a+bE(X)+cE(Y)

Then, using this property we have that E[C] = 50+3E[Y]+ 9E[Y^2].

Thus, we must calculate E[Y] and E[Y^2].

Using the definition, we get that

E[Y] = \int_{1}^{5}\frac{y}{4} dy =\frac{1}{4}\left\frac{y^2}{2}\right|_{1}^{5} = \frac{25}{8}-\frac{1}{8} = 3

E[Y^2] = \int_{1}^{5}\frac{y^2}{4} dy =\frac{1}{4}\left\frac{y^3}{3}\right|_{1}^{5} = \frac{125}{12}-\frac{1}{12} = \frac{31}{3}

Then

E(C) = 50 + 3\cdot 3 + 9 \cdot \frac{31}{3} = 152

5 0
3 years ago
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