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boyakko [2]
2 years ago
13

8. Assuming the density of your initial acid solution is 1.0 g/mL, what is the concentration (in molarity) of the diluted acetic

acid, [CH3COOH], solution
Chemistry
1 answer:
lawyer [7]2 years ago
3 0

Assuming the density of your initial acid solution is 1.0 g/mL.  the concentration (in molarity)  is mathematically given as

M= 0.75 M

<h3>What is the concentration (in molarity) of the diluted acetic acid, [CH3COOH], solution?</h3>

Generally, the equation for Molarity  is  mathematically given as

M= (W/MW) ×1000

Therefore

M= (\frac{4.5} {60.05} \frac{(1000}{ 100}

M = 0.75 M

In conclusion, The initial molarity  is given by

M= 0.75 M

Read more about molarity  

brainly.com/question/2817451

#SPJ1

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tankabanditka [31]

Answer:

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Explanation:

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3 years ago
What type of van der Waals interactions occur between molecules
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Given what we know, we can confirm that the type of van der Waals interactions that occur between molecules of O2, SCl2, and CH4 in liquids of these substances are the presence of <u>London dispersion forces</u>.

<h3>What are London dispersion forces?</h3>
  • They are a force of attraction between atoms.
  • They are generated by electrostatic attraction.
  • These forces are common between atoms in close proximity and occur often when compounds have a symmetrical distribution of atoms.
  • They are generated by the formation of temporary dipoles.

Therefore, given the symmetry of the atoms disposition in these compounds and the temporary dipoles generated by the atoms being in close proximity, we can confirm that the van der Waals forces present in each compound are London dispersion forces.

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7 0
2 years ago
Complete the sentence.
GREYUIT [131]

Answer:

Chemical change

Explanation:

7 0
4 years ago
Energy of an electron is not constant which it is in particular orbit ( true or false )​
WARRIOR [948]

Answer:

the answer is true

I hope it will help you

Explanation:

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5 0
3 years ago
A fat is composed of long chains of carbon and hydrogen atoms. In a reaction with a strong base, a fat forms a soap and glycerol
Nonamiya [84]

Answer:

Empirical formula is C₉H₁₅O

Molecular formula = C₈₁H₁₃₅O ₉

Explanation:

Percentage of carbon = 77.60%

Percentage of oxygen = 11.45%

Percentage of hydrogen = 10.95%

Molecular weight = 1253 g/mol

Molecular formula = ?

Empirical formula = ?

Solution:

Number of gram atoms of C = 77.60 g /12g/mol =6.5

Number of gram atoms of O = 11.45 g / 16 g/mol = 0.72

Number of gram atoms of H = 10.95 g / 1.008 g/mol= 10.9

Atomic ratio:

C               :            H                 :    O

6.5/0.72   :       10.9/0.72         :   0.72/0.72

     9          :            15              :         1

C : H : O = 9 : 15 : 1

Empirical formula is C₉H₁₅O

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

n = 1253 / 139

n = 9

Molecular formula = n (empirical formula)

Molecular formula = 9 (C₉H₁₅O )

Molecular formula = C₈₁H₁₃₅O ₉

4 0
4 years ago
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