The answer would be B. <span>One atom of sodium and one atom of fluorine</span>
Explanation: Electron dot structures are the lewis dot structures which represent the number of valence electrons around an atom in a molecule.
The electronic configuration of potassium is ![[Ar]4s^1](https://tex.z-dn.net/?f=%5BAr%5D4s%5E1)
Valence electrons of potassium are 1.
The electronic configuration of Bromine is ![[Ar]4s^24p^5](https://tex.z-dn.net/?f=%5BAr%5D4s%5E24p%5E5)
Valence electrons of bromine are 7.
These two elements form ionic compound.
Ionic compound is defined as the compound which is formed from the complete transfer of electrons from one element to another element.
Here, one electron is released by potassium which is accepted by bromine element. In this process, Potassium becomes cation having +1 charge and Bromine become anion having (-1) charge.
The ionic equation follows:

The electron dot structure is provided in the image below.
Answer:
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Explanation:
Answer:
The empirical formula for the compound is Na2O
Explanation:
Data obtained from the question include:
Sodium (Na) = 74.2g
Oxygen (O) = 25.8g
We can obtain the empirical formula for the compound as follow:
First, divide the above by their individual molar mass as shown below:
Na = 74.2/23 = 3.226
O = 25.8/16 = 1.613
Next, divide the above by the smallest number
Na = 3.226/1.613 = 2
O = 1.613/1.613 = 1
Therefore, the empirical formula is:
Na2O