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3 years ago

Simplify 3r (r - 10s) - 4r (7s + 2r)

Mathematics

2 answers:

aleksandrvk [35]3 years ago

5 0

HI!

Multiply the 3r to r and -10s

3r^2 - 30rs - 4r(7s+2r)

now multiply -4r to 7s and 2r

3r^2 - 30rs - 28rs - 8r^2

Now combine like terms

3-8 = -5

-30 - 28 = -58

-5r^2 - 58rs

Hope this helps!

Andrew [12]3 years ago

5 0

3r (r - 10s) - 4r (7s + 2r)

expand by using distributive property

3r^2 - 30rs - 28rs - 8r^2

combine like terms

-5r^2 - 58rs

Answer

-5r^2 - 58rs

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Answer:

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Step-by-step explanation:

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We are dividing:

$(x^2+5x+7)\div(x+k)$

So, a polynomial by a binomial factor.

Our factor is (x + k) or (x - (-k)). Using the form (x - a), our a = -k.

We want our remainder to be 3. So, P(a)=P(-k)=3.

Therefore:

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$k^2-5k+4=0$

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Zero Product Property:

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$(x^2+5x+7)\div(x+1)\text{ or } (x^2+5x+7)\div(x+4)$

Will yield 3 as the remainder.

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