I gotchu !! just give me a moment to write it out
A(n) = a₁.(r)ⁿ⁻¹, where a₁ = 1st term, r= common ratio and n, the rank
In the formula given a₁ = 5, r = 3/2 and n = 6 (we have to find the 6th term value).
a₆ = 5.(3/2)⁶⁻¹ = 5.(3/2)⁵ = 1215/32 (answer C)
Angle A is 29 and Angle B is 61. It’s problem can be solved by written the equation X+X+32=90. This becomes 2X+32=90 subtract 32 from each side making 2X=58 divide by 2 X=29 and just plug x in to solve for both angle names.
So, by multiplying the exponents, you would add all of the square roots together. For example for your question you would add 1+1+4+5=11 so the answer is c to the power of 11
Answer:
Function 1:
The starting point is (0,0.5)
As x increases, y increases
Function 2:
The starting point is (0,3)
As x increases, y decreases
Step-by-step explanation:
In order to find the starting point, we need to plug in x=0.


As we plug in increasing numbers into function#1, the y-value increases
As we plug in increasing numbers into function #2, the y-value is decreasing